![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer:
x= -1; y= -2
Step-by-step explanation:
A: 6x+4y= -14
B: -x-5y=11
6B is : -6x-30y=66
A+6B is : -26y=52
so y= -2
so A becomes : 6x+4.(-2)= -14
so x= -1
Some decimals between 0.55 and 0.56 are 0.551, 0.552, 0.553, 0.554, 0.556, 0.557, 0.558, 0.559.
i hope this is helpful
Your answer would be C im pretty sure
Answer:
When simplified its 8x^9 y^12
Step-by-step explanation:
