Answer:
I would say B because there are 15 1s
Center c and a scale factor of 2
Answer:
The 90% confidence interval for the mean test score is between 77.29 and 85.71.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 25 - 1 = 24
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.064
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29
The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.
The 90% confidence interval for the mean test score is between 77.29 and 85.71.
Answer:
There are 400 possible zip codes in the Houston area
Step-by-step explanation:
Here, we want to calculate the possible number of zip codes in the Houston area
We have 5 digits to form
77 is the first two digits ( this is fixed)
For the third digit, we are selecting 1 number out of 0,3,4 or 5
This means 4 C 1
The remaining digits can be any digits
We have 0-9, a total of 10 digits
The first will be 10 C 1 and the second last digit too is 10 C 1
So the number of possible zip codes will be;
4 C 1 * 10 C 1 * 10 C 1
= 4 * 10 * 10 = 400 possible zip codes
Answer:
Well, I kind of know this but I don't wanna be wrong so here and the sides if it helps
1. 2x8x8
2.2x8x8
3. 8x8x10x10