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zalisa [80]
3 years ago
8

Three people who work full-time are to work together on a project, but their total time on the project is to be equivalent to th

at of only one person working full-time. If one of the people is budgeted for one-half of his time to the project and a second person for onethird of her time, what part of the third worker’s time should be budgeted to this project? A. 1/3 B. 3/5 C. 1/6 D. 1/8
Mathematics
2 answers:
pantera1 [17]3 years ago
5 0
The problem tells us that the fractions of time worked by the three people need to be equivalent to one person working full time.  This means that the fractions need to add up to one.  We know one person works one-half (1/2) time on the project and another works one-third (1/3) time. Let x = the amount of time that the third person needs to work on the job to add up to one 1 = 1/2 + 1/3 + x 1 - 1/2 - 1/3 = x To subtract the fractions we need to put them all over a common denominator.  Let's use 3*2 = 6 as the denominator; so 1 = 6/6, 1/2 = 3/6, 1/3 = 2/6: 6/6 - 3/6 - 2/6 = x 1/6 = x The third person must work 1/6 time on the project.
Nataliya [291]3 years ago
3 0
I think that it is A.  because it is less than the otehrs
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Answer:

There are <u>20,000 milligrams</u> chlorine in the pool.

Step-by-step explanation:

Given:

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Now, to find the quantity of chlorine in the pool.

Let the quantity of chlorine be x.

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The milligrams of chlorine per liter of water in the pool = 2.5.

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So, 2.5 mg of chlorine is equivalent to 1 liter.

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Now, to get the quantity of chlorine by using cross multiplication method:

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3 years ago
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3 years ago
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Bogdan [553]

The number remaining for 19.35 to get to 25 is 5.65.

<h3>What is an expression?</h3>

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In this case, the number remaining for 19.35 to get to 25 will be:

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