Question 1 of 10

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

6 0

D. F(x)=x^2. That’s The quadratic parent function

sleet_krkn [62]3 years ago

6 0

A is a constant (k)
where k = 11

B is a linear (mx + c)
where m = 2 and c = 0

C is another linear (mx + c)
where m = 1 and c = 1

D is the quadratic function
(ax^2 + bx + c)
where a = 1, b = 0, c = 0.

Hence, the answer is D

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Kesara santiago purchased a riding mower for $2,746.00. she received a $49.95 rebate from the manufacturer and a $38.95 rebate f

andrew11 [14]

A rebate means that the buyer receives back a portion of the original price of the item. So in this case, the rebate prices must be deducted from the original price to get the final price, that is:

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NeX [460]

X-intercept: y = 0
y-intercept: x = 0

3x + 4y = 0

x-intercept: subtitute y = 0
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3 years ago

P is inversely proportional to the cube of (q-2) p=6 when q=3 find the value of p when q is 5

sveticcg [70]

$\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
\\
&&y=\cfrac{{{ k}}}{x}
\end{array}\\\\
-----------------------------\\\\
\textit{p is inversely proportional to the cube of (q-2)}\implies p=\cfrac{k}{(q-2)^3}
\\\\\\
now \quad 
\begin{cases}
p=6\\
q=3
\end{cases}\implies 6=\cfrac{k}{(3-2)^3}$

solve for "k", to find k or the "constant of variation"

then plug k's value back to $\bf p=\cfrac{k}{(q-2)^3}$

now.... what is "p" when q = 5? well, just set "q" to 5 on the right-hand-side, and simplify, to see what "p" is

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LenaWriter [7]

hyp*2 = opp*2 + adj*2

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a*2 + b*2 = c*2

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2 years ago

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How do you factor 4x²+28x <br>

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