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cricket20 [7]
3 years ago
5

Write an algebraic expression for the product of a number squared and 4

Mathematics
1 answer:
S_A_V [24]3 years ago
3 0
Let n represent unknown number
4n^2 is the final answer. Hope it help!
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Solve the system of equations
Blababa [14]

Answer:

x = 3

y = 1

Step-by-step explanation:

(2x + 4y = 10) * 2 = (4x + 8y =20)

4x = 20 - 8y

Plug that into the other equation

(20 - 8y) - y = 11

-9y = -9

y = 1

Plug this value into one of the original equations

2x + 4(1) = 10

2x = 6

x = 3

3 0
3 years ago
Read 2 more answers
2. A shirt that normally costs $30 is on sale for
exis [7]

Answer:27.5%

Step-by-step explanation:

To calculate the percentage discount between two prices, follow these steps:

  1. Subtract the post-discount price from the pre-discount price.
  2. Divide this new number by the pre-discount price.
  3. Multiply the resultant number by 100.
  4. Be proud of your mathematical abilities.
7 0
3 years ago
Go step by step to reduce the radical.<br> √216
iris [78.8K]

Answer: 6√6

Step-by-step explanation:

√216=

√(36*6)=6√6

5 0
2 years ago
What is the inverse of function f? f(x)=10/9+11
Lena [83]

Answer:

Option D is answer.

Step-by-step explanation:

Hey there!

Given;

f(x) = 10/9 X + 11

Let f(X) be "y".

y = (10/9) X + 11

Interchange "X" and "y".

x = (10/9) y + 11

or, 9x = 10y + 99

or, y = (9x-99)/10

Therefore, f'(X) = (9x-99)/10.

<u>Hope</u><u> it</u><u> helps</u><u>!</u>

6 0
3 years ago
Current rules for telephone area codes allow the use of digits​ 2-9 for the first​ digit, and​ 0-9 for the second and third​ dig
Anna35 [415]

Using the fundamental counting theorem, we have that:

  • 648 different area codes are possible with this rule.
  • There are 6,480,000,000 possible 10-digit phone numbers.
  • The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.

For the area code:

  • 8 options for the first digit.
  • 9 options for the second and third.

Thus:

8 \times 9 \times 9 = 648

648 different area codes are possible with this rule.

For the number of 10-digit phone numbers:

  • 7 digits, each with 10 options.
  • 648 different area codes.

Then

648 \times 10^7 = 6,480,000,000&#10;

There are 6,480,000,000 possible 10-digit phone numbers.

The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

A similar problem is given at brainly.com/question/24067651

5 0
2 years ago
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