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2 years ago

Find (f•g) (x) for the following functions.

Mathematics

1 answer:

Natasha2012 [34]2 years ago

6 0

Answer:

Step-by-step explanation:

f(x) * g(x)= (3x^2-4x-5)(11x-3)

33x^3-44x^2-55x-9x^2+12x+15

33x^3-53x^2-43x+15

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Plssss help meeee!!!

pogonyaev

The answer is c b/c you multiply

3 0

2 years ago

Read 2 more answers

Rewrite in Polar Form.... x^(2)+y^(2)-6y-8=0

skad [1K]

$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

3 0

2 years ago

How many sevenths are there in two wholes?

schepotkina [342]

Answer:

Step-by-step explanation:

7 times 2 = 14

7 0

2 years ago

Reason abstractly. Are all horizontal lines parallel? Use slope explain how you know.

ohaa [14]

Answer:

All horizontal lines are NOT parallel.

Step-by-step explanation:

We learned that lines go on forever.

If one line is slightly slanted, and the other line is completely straight, these lines are not parallel, as they will meet at some point.

Hope this helped :)

6 0

3 years ago

La empresa los manzanas exporta manzanas o varios paises del mundo, el lunes tiene que trasladar 300 cajones. Puede contratar ca

Mariulka [41]

Answer:

Para trasladar 300 cajones, las dos opciones cuestan los mismo. Son indiferentes entre si.

Step-by-step explanation:

Dada la siguiente información:

Cantidad de cajones= 300

Opción A:

Camiones con capacidad para 50 cajones que cobran 150 por viaje.

Cantidad de camiones= 300/50= 6

Opción B:

Camiones con capacidad de 60 cajones por 180 por viaje.

Cantidad de camiones= 300/60= 5

Debemos calcular el costo total de cada opción y elegir la de menor costo.

Costo total A= 150*6= $900

Costo total B=180*5= $900

Para trasladar 300 cajones, las dos opciones cuestan los mismo. Son indiferentes entre si.

5 0

2 years ago