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4 years ago

12

Tom is deciding whether or not he should become a member gym to use their basketball courts. The membership cost is $135. Member

s pay $2 to rent out the basketball courts. Non-members can rent the court also, but they have to pay $11 each time. how many times would Tom need to rent the court in order for it be cheaper to be a member than a non member?

1 answer:

Kisachek [45]4 years ago

6 0

135 + 2x
11x

135 + 30 (or 2 x 15) = 165
11 x 15 = 165

16 times.

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The rate is $\frac{2}{5}$ degree per hour.

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<img src="https://tex.z-dn.net/?f=9%20%5Cfrac%7B9%7D%7B10%7D%20%20%2B%202%20%5Cfrac%7B1%7D%7B4%7D%20%20%3D%20%20%5C%5C%20%206%20

frez [133]

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1. $445\frac{1}{2}$

2. $-1\frac{1}{12}$

3. $2\frac{11}{30}$

Step-by-step explanation:

1. $9\frac{9}{10} +2\frac{1}{4}$

I like to make it an improper fraction first.

$\frac{99}{10}+\frac{9}{4}$

Now take the LCM. The LCM is 20.

$\frac{198}{20} +\frac{45}{20}$

Now add them.

$\frac{8910}{20}$

Make this into a mixed number.

$445\frac{1}{2}$

That's your answer for number 1.

2. $6\frac{1}{4} -7\frac{1}{3}$

Do the same thing as the previous addition problem but subtract instead.

$\frac{25}{4} -\frac{22}{3}$

$\frac{75}{12} -\frac{88}{12}$

$-\frac{13}{12}=-1\frac{1}{12}$

$-1\frac{1}{12}$ is your answer for number 2.

3. $8\frac{2}{3}-6\frac{3}{10}$

$\frac{26}{3} -\frac{63}{10}$

$\frac{260}{30}-\frac{189}{30}$

$\frac{71}{30}=2\frac{11}{30}$

$2\frac{11}{30}$ is your answer for number 3.

I hope this helps! Let me know if you need help or if I got anything wrong :)

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3 years ago