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vovangra [49]
3 years ago
15

The table shows the area of a square with the given side length.

Mathematics
2 answers:
stepan [7]3 years ago
4 0
Y = x^2
.........................................
marysya [2.9K]3 years ago
3 0
Y=x squared

Every x squared equals y
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What is the answer?
lisov135 [29]

f is the answer hope it helps


4 0
3 years ago
Geometry area question. Please help!
timurjin [86]
You can calculate polygon area with only apothem OR side length.

apothem only
area = apothem^2 * 6 * tan (180/6)
area = 10.4^2 * 6 * 0.57735
area = 108.16 * <span> <span> <span> 3.4641 </span> </span> </span>
area = <span> <span> <span> 374.677056 </span> </span> </span> square yards

side length only
area = 6 * 12^2 * / 4*tan(30)
area = 864 / 4 * 0.57735
area = 864 / <span> <span> <span> 2.3094 </span> </span> </span>
area = <span> <span> <span> 374.1231488698 </span> </span> </span> square yards

If apothem and side length were given with more precision, the answers would be closer.

Source:
http://www.1728.org/polygon.htm


5 0
3 years ago
Q)David bed is 9 inches longer than his desk His desk is 66 inches long .
Luda [366]

Answer:75 inches

Step-by-step explanation: 9+66=75

=75 inches

8 0
3 years ago
Read 2 more answers
Write an algebraic expression for 3 times x 2 times x minus 4 times x
Tpy6a [65]

Answer:

(3+2)x - 4x

Step-by-step explanation:

I just converted the words, turned them to operations and that's it!

Hope this helps! :D

- Anna

8 0
3 years ago
The radius r(t)r(t)r, (, t, )of the base of a cylinder is increasing at a rate of 111 meter per hour and the height h(t)h(t)h, (
sp2606 [1]

Answer:

The volume is decreasing at a rate 20π cubic meter per hour.

Step-by-step explanation:

We are given the following in the question:

The radius is increasing at a rate 1 meter per hour.

\dfrac{dr}{dt} = 1\text{ meter per hour}                

The height is decreasing at a rate 4 meter per hour  

\dfrac{dh}{dt} = -4\text{ meter per hour}

At an instant time t,

r = 5 meter

h = 8 meters

Volume of cylinder =

\pi r^2 h

where r is the radius and h is the height of the cylinder.

Rate of change of volume is given by:

\dfrac{dV}{dt} = \dfrac{d(\pi r^2 h)}{dt}\\\\\dfrac{dV}{dt} = 2\pi rh\dfrac{dr}{dt} + \pi r^2\dfrac{dh}{dt}

Putting all the values we get,

\dfrac{dV}{dt} = 2\pi (5)(8)(1) + \pi (5)^2(-4)\\\\\dfrac{dV}{dt} = 80\pi - 100\pi = -20\pi \approx -62.8

Thus, the volume is decreasing at a rate 20π cubic meter per hour or 62.8 cubic meter per hour.      

3 0
3 years ago
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