There are infinity of fractions equal to 1/2, it just means half of a number, so for example, 3/6, 4/8, 5/10, 6/12 are all equal to 1/2 and so on
Answer:
A≈1017.88 if r=18m or A≈254.47 if r=9
Step-by-step explanation:
A=Pi*r^2, plugging in 18 m or 9 m since lack of info but i assume you are giving 18m total length of circle, gives us answer.
Answer: A) 18.2 minutes
B) 4.5 minutes.
Step-by-step explanation:
A) Maxine can mow one lawn in 24 minutes, so the rate of work is:
1/24 of the lawn per minute.
Sammie can mow one lanw in 36 minutes, so the rate of work is:
1/36 of the lawn per minute.
The amount of the lawn that each has left to lawn by the minute x is:
Maxine = 1 -(1/24)*x
Sammie = 1 - (1/36)*x
we want to find the value of x such that:
2*(1 - (1/24)*x) = 1 - *(1/36)*x
which means that the amount that Sammie has left is two times the amount that Maxine has left to mow.
2 - (1/12)*x = 1 - (1/36)*x
2 - 1 = (1/12 - 1/36)*x
1/0.055 = x = 18.2
by the minute 18.2
B) Similar to before, here the rates are:
For Maxine, R = 1/6
For Sammie, R = 1/9
The amount they have left to mow by minute x is:
Maxine = 1 - (1/6)*x
Sammie = 1 - (1/9)*x
We want to solve, similar to before.
2( 1 - (1/6)*x) = 1 - (1/9)*x
2 - (1/3)*x = 1 - (1/9)*x
2 - 1 = (1/3 - 1/9)*x
1 = (2/9)*x
1*9/2 = x = 4.5
So here the solution is 4.5 minutes. Hope this helps
Answer:
They have 5 packages of pancake mix.
N(p) = 140*p
Represents the number of people that can be feed with p = # of packages of pancake mix used.
Now, the domain will be the set of the possible values of p that we can use here.
the set of possible values of p will be:
{0, 1, 2, 3, 4, 5}
We can not use more than 5 because there are only 5 packages.
But we can use actually half a package or a third, so we not should use only whole numbers in the domain, then the domain can be written as:
D = 0 ≤ p ≤ 5
Now, the range is the set of the possible values of N(p)
The minimum will be when p = 0.
N(0) = 140*0 = 0
The maximum will be when p = 5
N(5) = 140*5 = 700
Then the range can be written as:
R = 0 ≤ N ≤ 700
Here we could add another restriction, because we can only feed a whole number of people, then we also should add the restriction that N must be a whole number:
R = 0 ≤ N ≤ 700, N ∈ Z
Sent a picture of the solution to the problem (s).
