You have to use the method of FOIL (first, outer, inner and Last)
9b*9b is first
9b*1 is outer
-1*9b is inner
-1*1 is last
Together, they form the expression 81b^2 + 9b - 9b - 1
Collect like terms and the answer is 81b^2 - 1
Step-by-step explanation:
first distribute
6x - 36 + 4 = 32 + 6x
combine like terms
6x - 32 = 32+ 6x
subtract 6x from both sides and add 32
0 = 64
therefore no solutions to this problem
Answer:
a. 13 years
b. 27950 students
Step-by-step explanation:
Let x be the number of years since the initial year 2005. In 2005,
, in 2006,
, and so on.
For college "A" the number of students is given by the function:
![NSA = 18200 + 750x](https://tex.z-dn.net/?f=NSA%20%3D%2018200%20%2B%20750x)
For college "B" the number of students is given by the function:
![NSB = 34450 - 500x](https://tex.z-dn.net/?f=NSB%20%3D%2034450%20-%20500x)
Matching these expressions you have the value of x for which the two colleges have the same number of students.
![NSA = 18200 + 750x = 34450 - 500x = NSB\\\\750x + 500x = 34450 - 18200\\\\1250x = 16250\\\\x = 16250/1250 = 13](https://tex.z-dn.net/?f=NSA%20%3D%2018200%20%2B%20750x%20%3D%2034450%20-%20500x%20%3D%20NSB%5C%5C%5C%5C750x%20%2B%20500x%20%3D%2034450%20-%2018200%5C%5C%5C%5C1250x%20%3D%2016250%5C%5C%5C%5Cx%20%3D%2016250%2F1250%20%3D%2013)
Then, the two colleges will have the same number of students 13 years later, that is, in 2018.
The number of students that each colleges will have in 2018 will be
students.
This good question needs a good answer which is......854.96
Answer:
Q3 = 85
Step-by-step explanation:
Do the same thing you do to find the median for the numbers 70 to 96, i.e. exclude the numbers less than the median.