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3 years ago

Find the range of the graphed function

Mathematics

2 answers:

stich3 [128]3 years ago

8 0

Answer:

$A.\:-4\le y\le 8$ .

Step-by-step explanation:

The range of the range of the function refers to the y-values for which x is defined.

Observe that there are 5 boxes from 0 to 10 on the y-axis.

This means that each box is 2 units.

From the graph the least y-value is $-4$ and the highest y-value is 8.

The range is $-4\le y\le 8$ .

Illusion [34]3 years ago

4 0

Answer:

Correct choice is A

Step-by-step explanation:

The range of the function are all possible values which variable y can take.

From the given diagram you can see that the variable x changes from -4 to the 9. So the domain of the function is $-4\le x\le 9.$

Also the variable y takes its values from -4 to 8. Thus, the range is $-4\le y\le 8.$

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3 years ago

The frequency distribution shows the number of registered motor vehicles for a random sample of 200 California households.

erastovalidia [21]

Answer:

1). Mean = 2.275

2). Median = 2 vehicles

Step-by-step explanation:

From the given table,

Number of vehicles (x) Frequency (f) (f)×(x) Cumulative freq.

0 11 0 11

1 52 52 63

2 66 132 129

3 35 105 164

4 19 76 183

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= $\frac{455}{200}$

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2 years ago

A force of 12 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i

sattari [20]

Answer:

Work done in stretching the spring = 7.56 lb-ft.

Step-by-step explanation:

Normal length of the spring = 8 in or $\frac{8}{12}$ ft

= $\frac{2}{3}$ ft

If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in

= $\frac{11}{12}$ ft

Force applied to stretch the spring = 12 lb

By Hook's law,

F = kx [where k is the spring constant and x = length by which the spring is stretched]

12 = k( $\frac{2}{3}$ )

k = 18

Work done (W) to stretch the spring by $\frac{11}{12}$ ft will be

W = $\int\limits^\frac{11}{12} _0 {kx} \, dx$

= $\int\limits^\frac{11}{12} _0 {(18x)} \, dx$

= $18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0$

= 9( $\frac{11}{12}$ )²

= 7.56 lb-ft

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2 years ago

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Answer:

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3 years ago