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3 years ago

Ixl is mean so will you help me ? :))

Mathematics

2 answers:

Sever21 [200]3 years ago

7 0

64 is the answer lololo

almond37 [142]3 years ago

5 0

I think its 64in^2.
hope this helps.

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The mean weight 20 students in a room is 65 kg one student one student who weight is 88kg went into the room what is the new mea

umka2103 [35]

The new mean is 66.09

Explanation:

Mean weight of 20 students = 65kg

One student with 88kg entered the room.

New mean = ?

$\frac{x_1+x_2+....+x_2_0}{20} = 65$

$\frac{x_1+x_2+....+x_2_0 + 88}{21} = ?$

The above equation can further be written as:

$x_1 + x_2 +....+x_2_0 = 65 X 20\\\\x_1 + x_2 +....+x_2_0 = 1300$

New mean = $\frac{1300 + 88}{21}$

= 66.09

Therefore, the new mean is 66.09

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2 years ago

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melisa1 [442]

Answer:

Step-by-step explanation:

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2 years ago

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cluponka [151]

Answer:

Step-by-step explanation:

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2 years ago

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Question 14 of 20 :

LenKa [72]

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3 years ago

(1 point) A random sample of 600 movie goers in Flagstaff found 252 movie goers who had bought popcorn on their last visit. Find

garik1379 [7]

Answer-

A 95% confidence interval for the true percent of movie goers is 36.41% to 44.25%

Solution-

Given,

n = 600 (sample size)

x = 252 (number of people who bought)

Confidence interval = 95%, so z = 1.96

We know that,

$\mu = M\pm Z(SE)$

where,

M = sample mean

Z = Z statistic determined by confidence level

SE = standard error of mean

Calculating the values,

$M=\frac{x}{n} =\frac{242}{600} =0.4033$

$Z=1.96$ from the tables

$SE=\sqrt{\frac{M\times (1-M)}{n}}$

$\Rightarrow SE=\sqrt{\frac{0.4033\times (1-0.4033)}{600}}=0.02$

Putting all the values in the formula,

$\mu = M\pm Z(SE)$

$\mu = 0.4033\pm 1.96(0.02)$

$=0.4033\pm 0.0392$

$=0.4425, 0.3641$

$= 44.25\%,36.41\%$

5 0

3 years ago