Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
Step-by-step explanation:
Friends lunch=8+8+8=$32
Blake's lunch=$6
32+6=$40 total
Answer:
<h2>17</h2>
Step-by-step explanation:
Use PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
Answer:
Step-by-step explanation:
Use proportions to solve.
Corresponding sides have same ratio.
<u>Question 1</u>
- (6x + 3)/17 = (8x - 1)/21
- 21(6x + 3) = 17(8x - 1)
- 126x + 63 = 136x - 17
- 10x = 80
- x = 8
<u>Question 2</u>
- (x + 8)/21 = 32/28
- x + 8 = 21*8/7
- x + 8 = 24
- x = 24 - 8
- x = 16
