All categories

3 years ago

How do I solve it. I am having trouble getting the answer

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

3 0

Answer:

Step-by-step explanation:

break it down as many times as you can. how? just keep dividing each by 2. example: 85 divided by 2 is 42.5 so under both arrows put 42.5. then divide that by 2. 42.5 divided by 2 is 21.25. keep dividing until you cant no more

You might be interested in

Which is an example of a statistical question?

kari74 [83]

Answer:

Question 2

Step-by-step explanation:

divdtihcdyuvftujvfujvfubf

5 0

3 years ago

Read 2 more answers

Solve the problem.

choli [55]

Answer:

6 $\frac{3}{100}$

Step-by-step explanation:

$603 dollars ÷ 100 shoppers = $6.03 per shopper, or 6 $\frac{3}{100}$ as a mixed number

4 0

3 years ago

A log splitter can split 6 5 cords of wood in 4 5 of a hour. Compute the unit rate by setting up a complex fraction and simplify

Aleksandr-060686 [28]

The answer is 1.5 or 1 1/2.
here is the how you get this answer.
1: Cross Multiply (1.2)(60)=x
2: divide x by 48
3: you should get 1.5 or 3/2

BTW x is equal to 72

7 0

3 years ago

Read 2 more answers

Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x

iren [92.7K]

Answer:

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

$2x^2+1=5x$

$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$