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3 years ago

21 times what is 126?

Mathematics

2 answers:

xz_007 [3.2K]3 years ago

5 0

Do you mean 21 x 126?

goldfiish [28.3K]3 years ago

5 0

21 X 126 is 2,646

I hope this answers your question
~Renee \(^_^)/

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(6x-5y+4)dy+(y-2x-1)dx=0

Len [333]

(6x - 5y + 4) dy + (y - 2x - 1) dx = 0

(6x - 5y + 4) dy = (2x - y + 1) dx

dy/dx = (2x - y + 1) / (6x - 5y + 4)

Let X = x - a and Y = y - b. We want to find constants a and b such that

dY/dX = (a rational function)

where the numerator and denominator on the right side are free of constant terms. Substituting x and y in the equation, we have

dY/dX = (2 (X + a) - (Y + b) + 1) / (6 (X + a) - 5 (Y + b) + 4)

dY/dX = (2X - Y + 2a - b + 1) / (6X - 5Y + 6a - 5b + 4)

Then we solve for a and b in the system,

2a - b + 1 = 0

6a - 5b + 4 = 0

==> a = -1/4 and b = 1/2

With these constants, the equation reduces to

dY/dX = (2X - Y) / (6X - 5Y)

Now substitute Y = VX and dY/dX = X dV/dX + V :

X dV/dX + V = (2X - VX) / (6X - 5VX)

The equation becomes separable after some simplification:

X dV/dX + V = (2 - V) / (6 - 5V)

X dV/dX = (2 - V) / (6 - 5V) - V

X dV/dX = (2 - V - (6 - 5V)) / (6 - 5V)

X dV/dX = (4V - 4) / (6 - 5V)

- (5V - 6) / (4V - 4) dV = 1/X dX

Integrate both sides:

-5/4 V + 1/4 ln|4V - 4| = ln|X| + C

Extract a constant from the logarithm on the left:

-5/4 V + 1/4 (ln(4) + ln|V - 1|) = ln|X| + C

-5/4 V + 1/4 ln|V - 1| = ln|X| + C

-5V + ln|V - 1| = 4 ln|X| + C

Get this back in terms of Y :

-5Y/X + ln|Y/X - 1| = 4 ln|X| + C

Now get the solution in terms of y and x :

-5 (y - 1/2)/(x + 1/4) + ln|(y - 1/2)/(x + 1/4) - 1| = 4 ln|x + 1/4| + C

With some manipulation of constants and logarithms, and a bit of algebra, we can rewrite this solution as

-5 (4y - 2)/(4x + 1) + ln|(4y - 4x - 3)/(4x + 1)| = 4 ln|x + 1/4| + 4 ln(4) + C

-5 (4y - 2)/(4x + 1) + ln|(4y - 4x - 3)/(4x + 1)| = 4 ln|4x + 1| + C

-5 (4y - 2)/(4x + 1) + ln|4y - 4x - 3| - ln|4x + 1| = 4 ln|4x + 1| + C

-5 (4y - 2)/(4x + 1) + ln|4y - 4x - 3| = 5 ln|4x + 1| + C

8 0

3 years ago

Find the average value of f(x)=e2x over the interval [2, 4].

shusha [124]

<h2>Option B is the correct answer.</h2>

Step-by-step explanation:

We need to find average value of $e^{2x}$ in [2,4]

Area of $e^{2x}$ in [2,4] is given by

$\int_{2}^{4}e^{2x}dx=\frac{1}{2}\times \left [ e^{2x}\right ]^4_2\\\\\int_{2}^{4}e^{2x}dx=\frac{1}{2}\times(e^8-e^4)=1463.18$

Area of $e^{2x}$ in [2,4] = 1463.18

Difference = 4 - 2 = 2

Average value = Area of $e^{2x}$ in [2,4] ÷ Difference

Average value = 1463.18 ÷ 2

Average value = 731.59

Option B is the correct answer.

5 0

3 years ago

12k+5=k+49 what's the answer

dybincka [34]

The answer is k=4 you're welcome

3 0

3 years ago

Name:

lubasha [3.4K]

Answer:

3,225

Step-by-step explanation:

principal times interest time rate

4 0

2 years ago

Y=33x+102 what is Y?

rusak2 [61]

Answer:

you have y so i will guess u mean x your answer for x will be

Step-by-step explanation:

since 33 is ur first number and 11 evenly goes into 33 it will be

Y 34

Y= ----- SUBTRACTED BY -------

33 11

<h2>Y EQUALS Y OVER 33 MINOUS 34OVER 11</h2>

8 0

3 years ago