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3 years ago

8

On Wednesday, Danielle skated 2/3 of the way around the track in 2 minutes. Her younger brother skated 3/4 of Danielle's distanc

e in 2 minutes. What fraction of the track did Danielle's brother finish in 2 minutes?

1 answer:

katen-ka-za [31]3 years ago

4 0

75 percent of 2/3

Is 0.5 of the way

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Tom had a total of $220 and he spent $35 on a basketball ticket . What percent of his money did he have left?

RoseWind [281]

Answer: 84.09%

Step-by-step explanation:

1. 220-30=? ?=185

2. Divide 185 by 220 (as a fraction, 185 out of 220 is 185/220 which also means divide) 185 divided by 220 is about 0.8409

3. Multiply 0.8409 by 100 (since there is two zeros in 100 we can move the decimal to the right twice which gets you 84.09

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3 years ago

What is the rate of change between (1,15) (3,45)?

Ksivusya [100]

Answer:

15

Step-by-step explanation:

Rate of change or slope or gradient of a line passes two points (x1, y1) and (x2, y2) could be calculated by:

(y2 - y1)/(x2 - x1)

=> Rate of change of the line passing (1,15) and (3,45):

(45 - 15)/(3 - 1) = 30/2 = 15

3 0

3 years ago

A psychology class consists of 14 males and 36 females. if the professor selects name from the class list using random sampling,

Pavel [41]

The total number of students is 14+36, or 50. So the chance that a selected student is female is 36/50, or 18/25.

3 0

3 years ago

Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d

Olegator [25]

Answer:

The speed of the cars is $32 \frac{km}{h}$

Step-by-step explanation:

First we must first have the clear concept that $speed=\frac{distance}{time}$ or $s=\frac{d}{t}$

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: $s_{1}=s+1$ , $t_{1}=2$ and $d_{1}= d_{2}$

Car 1: $s_{2}=s-10$ , $t_{2}=3$ and $d_{1}= d_{2}$

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

$d_{1}=s_{1}*t_{1}$

$d_{1}=(s+1)*2$

$d_{1}=2s+2$

<em>Car 2</em>

$d_{2}=s_{2}*t_{2}$

$d_{2}=(s-10)*3$

$d_{2}=3s.30$

$d_{1}=d_{2}$

$2s+2=3s-30$

$2+30=3s-2s$

$32=s$

The speed of the cars is 32 km/hr

7 0

3 years ago

Please help meeeeeeeeeeeeeeeee

Ganezh [65]

Am not sure but i think it would be A

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3 years ago

Read 2 more answers