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babunello [35]
2 years ago
10

V = u + at u = 2 a = -7 t = 0.5

Mathematics
1 answer:
VashaNatasha [74]2 years ago
8 0

v= u+ at

just put value bruuhh u can't even do this? alright

v=2+ (-7)(0.5)

v= -1.5

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PLZ HELP ASAP Geometry help: 2x^2 + 2y^2 - 8x +10y +2=0
Alexxx [7]
Ok so this is conic sectuion
first group x's with x's and y's with y's
then complete the squra with x's and y's


2x^2-8x+2y^2+10y+2=0
2(x^2-4x)+2(y^2+5y)+2=0
take 1/2 of linear coeficient and square
-4/2=-2, (-2)^2=4
5/2=2.5, 2.5^2=6.25
add that and negative inside

2(x^2-4x+4-4)+2(y^2+5y+6.25-6.25)+2=0
factor perfect squares
2((x-2)^2-4)+2((y+2.5)^2-6.25)+2=0
distribute
2(x-2)^2-8+2(y+2.5)^2-12.5+2=0
2(x-2)^2+2(y+2.5)^2-18.5=0
add 18.5 both sides
2(x-2)^2+2(y+2.5)^2=18.5
divide both sides by 2
(x-2)^2+(y+2.5)^2=9.25

that is a circle center (2,-2.5) with radius √9.25

6 0
2 years ago
there arre 221 students on a fiel trip five students ride in a van the rest of the students fill the 6 buses enter an equation t
iren2701 [21]

According to the question statement, the total sum of students is 221, which includes the students that ride on bus and the students that ride in a van.

The students that ride in a van are five, the students that ride on bus are 6 times s which is the product of the number of buses and the number of students that are on each bus.

Write all this information into an equation, this way:

6s+5=221

Now, solve the equation for s to find the number of students that are on each bus.

\begin{gathered} 6s+5=221 \\ 6s=216 \\ s=\frac{216}{6} \\ s=36 \end{gathered}

There are 36 students on each bus.

3 0
1 year ago
Ez points!!!!! what is 3+3/3
scoray [572]

Answer:

2

Step-by-step explanation:

3 plus 3 is 6 then divided by 3 is 2

8 0
3 years ago
Read 2 more answers
What is the constant of proportionality y/x if y=40 and x=1
Anastasy [175]
The c.o.p would be 40
7 0
3 years ago
Rich is comparing the cost of maintaing his car with the depreciating value of the car. When will the cost and value be the same
goldfiish [28.3K]

Complete question:

Rich is comparing the cost of maintaining his car with the depreciation value of the car.

The value starts at $20,000 and decreases by 15% each year. The maintanance cost is $500 the first year and increases by 28% per year.

When will the maintenance cost and the value be the same.

Answer:

9 years

Step-by-step explanation:

Depreciation is modeled by an exponential function :

A = p(1 - r)^t [decrease, '-']

A = 20,000(1 - 0.15)^t

A = 20000(0.85)^t - - - (1)

Maintainace cost :

A = p(1 + r)^t ; [increase, '+']

A = 500(1 + 0.28)^t

A = 500(1.28)^t - - - (2)

Equating (1) and 2

20000(0.85)^t = 500(1.28)^t

1.28^t / 0.85^t = 20000/500

(1.28 / 0.85)^t = 40

Take log of both sides

Log (1.28 / 0.85)^t = log 40

t * 0.1777910 = 1.6020599

t = 1.6020599 / 0.1777910

t = 9.01

t = 9 years

8 0
3 years ago
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