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yan [13]
3 years ago
7

PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!! Simplify. 3√-50

Mathematics
1 answer:
3241004551 [841]3 years ago
7 0

3√(-50) = 3√(-1*50)=3i√(25*2) = 3*5i√2=15i√2

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Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

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2 years ago
17, 24, 31, 38, ... common diffrence Arithmetic Sequences
irinina [24]

Ans: 10+7n

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3 years ago
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Mr.Eastman drew triangle JKL,with a height of 12 inches and a base of 12 inches, and triangle XLZ, with a height of 8 inches and
34kurt

Answer:

Step-by-step explanation:

Area of triangle = 1/2 × Base × Height

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Area of JKL = 1/2 × 12 inches × 12 inches

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ololo11 [35]
Probably B

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Amanda placed her finger on the origin of a regular coordinate plane. She marked a point after moving her finger 1 unit to the l
Lubov Fominskaja [6]

Answer:

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Step-by-step explanation:

Solution:-

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- Similarly, The values on the vertical axis also known as the y-axis is marked with a referece of y = 0 ( origin ). All the values to the above the point of origin are denoted as positive units and all values below of the point of origin are denoted as negative units.

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In other words, if +x is pointing to the right then the +y will be pointed in the direction when +x is rotated counter clockwise to 90 degrees; hence, points upward.

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