Find a parametrization r ( t ) r(t) of the line through the origin whose projection on the x y - xy- plane is a line of slope 8
8 and on the y z - yz- plane is a line of slope 3 3 (i.e. Δ y Δ z = 3 ). ΔyΔz=3). Consider the first component of r ( t ) r(t) is t .
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Answer:
15<em>y</em> = -28 <em>x</em> + 205.
Step-by-step explanation:
Slope intercept form of equation is <em>y = mx + c</em> where m is slope and c is the y intercept.
Now slope of line passing through points (-5, 23) and (10, -5):
Now equation of line:
<em> y = mx + c</em>
substituting the value of m in above expression,
Now, since the line is passing through the point (-5, 23) therefore, x = -5 and y = 23. By substituting these values in above equation,
So equation of line in slope intercept form:
Further solving,
15<em>y</em> = -28 <em>x</em> + 205.