A sicitrist might help you or go to a doctor and get some marijawana
Answer
Given,
Sound Power, P = 600 W
a) Intensity of sound,
r = 5 m
we know,
I = 1.91 W/m²
b) Sound intensity
I₀ = 10⁻¹²
c) Sound experienced by the Phil
β₁ = 123 - 23 = 100 \ dB
distance from the sound
again using sound intensity formula
where, I = P/A
r = 69.09 m
Distance where Phil will experience same sound intensity without earplug is equal to r = 69.09 m
<h3>
Answer:</h3>
<h3>
Explanation:</h3>
_______________
h=7,5 m
g=10 m/s²
ρ=1000 kg/m³
_______________
p - ?
_______________
p=ρgh=1000 kg/m³ · 10 m/s² · 7,5 m = 75000 Pa = 75 kPa
A body of mass 2kg is at rest. A force of 20N makes it move with a velocity of 5m/s, the impulse of the body would be 10 Kgm/s
<h3>What is impulse?</h3>
The product of the average applied force and the time for which it is exerted is known as an impulse. The unit for the impulse of force is the same as that of momentum which is kg*m/s
The mathematical relation for impulse is
Impulse = F * Δt =change in momentum
As given in the problem body of mass of 2 kg is at rest. A force of 20N makes it move with a velocity of 5m/s
Change in the momentum of the body
Δm = m(v₂-v₁)
As the body was initially at rest v₁ =0
Δm = 2×5
Δm = 10 Kgm/s
As we know that change in the momentum represents the impulse of the force
Thus, the impulse of the body would be 10 Kgm/s
Learn more about impulse, here
brainly.com/question/16980676
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