At a distance 30 m from a jet engine, intensity of sound is 10 W/m^2. What is the intensity at a distance 180 m?

Physics

1 answer:

AleksandrR [38]2 years ago

5 0

Answer:

$I_{2}=0.27 W/m^2$

Explanation:

Intensity is given by the expresion:

$I_{2}=Io (\frac{r1}{r2} )^{2}$

where:

Io = inicial intensity

r1= initial distance

r= final distance

$I_{2}=10 W/m^2 (\frac{30m}{180m} )^{2}$

$I_{2}=0.27 W/m^2$

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