Answer:
because the light bounces off of the water creating a bend. the answer is d.
We can utilize the equation pi=pf (p=momentum). because p=mv, we can sub in the initial masses and velocities as well as the finals in order to form an equation. this results in 120(4)+100(3)=120(2)+100x. this can be simplified to 540=100x, or x=5.4 m/s.
Answer:
when the player’s foot is in contact with the ball
Explanation:
Answer:
m = 27752.7 [kg]
Explanation:
To solve this problem we must first use the following equation of kinematics.

where:
Vf = final velocity = 240 [km/h]
Vo = initial velocity = 0
a = acceleration [m/s²]
t = time = 2 [s]
But first we must convert the speed from kilometers per hour to meters per second.
![240[\frac{km}{h} ]*(\frac{1h}{3600s} )*(\frac{1000m}{1km} )=66.67[m/s]](https://tex.z-dn.net/?f=240%5B%5Cfrac%7Bkm%7D%7Bh%7D%20%5D%2A%28%5Cfrac%7B1h%7D%7B3600s%7D%20%29%2A%28%5Cfrac%7B1000m%7D%7B1km%7D%20%29%3D66.67%5Bm%2Fs%5D)
Now replacing:
![66.67 = 0 +a*2\\a = 33.33 [m/s^{2} ]](https://tex.z-dn.net/?f=66.67%20%3D%200%20%2Ba%2A2%5C%5Ca%20%3D%2033.33%20%5Bm%2Fs%5E%7B2%7D%20%5D)
Now using Newton's second law which is defined as the product of mass by acceleration we can determine the mass of the jet.
∑F = m*a
![925000=m*33.33\\m = 925000/33.33\\m = 27752.7 [kg]](https://tex.z-dn.net/?f=925000%3Dm%2A33.33%5C%5Cm%20%3D%20925000%2F33.33%5C%5Cm%20%3D%2027752.7%20%5Bkg%5D)
188m - 556m is the wavelength range for AM radio.
2.77 - 3.40m is the wavelength range for FM radio.
1) For AM radio
f(max) = 1600 × 10³ Hz
f(min) = 540 ×10³Hz
c = fλ
λ = c/f where,
c = speed of light
f = frequency
λ= wavelength
So,
λ(min) = 3 ×
/ 1600 × 10³ = 188 m
λ(max) = 3 × 10⁸/540 ×10³ = 556 m
So wavelength range of AM radio is 188 m - 556m
2) For FM radio
f(max) = 108 × 10⁶ Hz
f(min) = 88 × 10⁶ Hz
λ(min) = 3 × 10⁸ / 108 × 10⁶ = 2.77 m
λ(max) = 3 × 10⁸ / 88 × 10⁶ = 3.40 m
So wavelength range of FM radio is 2.77m - 3.40m
Learn more about frequency here brainly.com/question/10728818
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