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Ostrovityanka [42]

2 years ago

6

A tank with a flat bottom is filled with water to a height of 7.5 meters. What's the pressure at any point at the bottom of the

tank? (Ignore atmospheric pressure in your calculations.)

1 answer:

Ivanshal [37]2 years ago

5 0

<h3>Answer:</h3>

p=75 kPa

<h3>Explanation:</h3>

_______________

h=7,5 m

g=10 m/s²

ρ=1000 kg/m³

_______________

p - ?

_______________

p=ρgh=1000 kg/m³ · 10 m/s² · 7,5 m = 75000 Pa = 75 kPa

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Consider the same roller coaster. It starts at a height of 40.0 m but once released, it can only reach a height of 25.0 m above

poizon [28]

Answer:

The magnitude of the frictional force between the car and the track is 367.763 N.

Explanation:

The roller coster has an initial gravitational potential energy, which is partially dissipated by friction and final gravitational potential energy is less. According to the Principle of Energy Conservation and Work-Energy Theorem, the motion of roller coster is represented by the following expression:

$U_{g,1} = U_{g,2} + W_{dis}$

Where:

$U_{g,1}$ , $U_{g,2}$ - Initial and final gravitational potential energy, measured in joules.

$W_{dis}$ - Dissipated work due to friction, measured in joules.

Gravitational potential energy is described by the following formula:

$U = m \cdot g \cdot y$

Where:

$m$ - Mass, measured in kilograms.

$g$ - Gravitational constant, measured in meters per square second.

$y$ - Height with respect to reference point, measured in meters.

In addition, dissipated work due to friction is:

$W_{dis} = f \cdot \Delta s$

Where:

$f$ - Friction force, measured in newtons.

$\Delta s$ - Travelled distance, measured in meters.

Now, the energy equation is expanded and frictional force is cleared:

$m \cdot g \cdot (y_{1} - y_{2}) = f\cdot \Delta s$

$f = \frac{m \cdot g \cdot (y_{1}-y_{2})}{\Delta s}$

If $m = 1000\,kg$ , $g = 9.807\,\frac{m}{s^{2}}$ , $y_{1} = 40\,m$ , $y_{2} = 25\,m$ and $\Delta s = 400\,m$ , then:

$f = \frac{(1000\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (40\,m-25\,m)}{400\,m}$

$f = 367.763\,N$

The magnitude of the frictional force between the car and the track is 367.763 N.

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3 years ago

What is the problem with using your boat's engine to drive it onto a trailer?

Elenna [48]

Silt and other wash can accumulate behind the motor and if other boats are added they can get their hulls damaged or scraped then, depending on the size of the material. It can also cause trailers to get stuck if they drive into the place from where the boat came.

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4 years ago

How long does it take the moon to go through an entire set of phases?.

Bas_tet [7]

It take <u>approximately 29</u><u>.</u><u>5 </u><u>days</u> for moon to do its entire set of phases.

<h3>Explanation</h3>

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With that, the moon has two periods of revolution, namely:

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a dog usually moves faster than a bug . That means that if i watch them move for one minute, then the dog would have traveled a

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The dog would have traveled a greater distance than the bug.
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Hope this helps! Have a great day :)

(ps. brainliest, please?)

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3 years ago

igor_vitrenko [27]

Good morning love ya good morning Mrs thanks love you bye bye thanks again for your birthday wishes bye

6 0

3 years ago

Read 2 more answers