Question

The distance between Quebec City and New York City is 520 miles. If Kate leaves Quebec and will leaves New York at 9 am and the drive towards each other at 55 mph and 75 mph respectively at what time will they meet

Answer 1

Answer:they would meet at 1 pm

Step-by-step explanation:

The distance between Quebec City and New York City is 520 miles.

At the point where Kate and Will meet, they would have travelled 520 miles.

Let t represent the time it takes Kate to travel a certain distance before they met.

Distance = speed × time

If Kate drives at 55mph, the distance covered would be

55 × t = 55t.will drives at 75 mph

Since Will left same that that Kate left, distance travelled by Will in t hours would be

75 × t = 75t

Since the total distance covered is 520 miles, it means that

55t +75t = 520

130t = 520

t = 520/130 = 4

9 am + 4 hours = 1 pm

Answer 2

Answer:

  1 pm

Step-by-step explanation:

Their combined speed is 55 + 75 = 130 miles per hour. That is the rate at which the distance between them is decreasing. The time it takes for the distance between them to become zero is found from the relation ...

  time = distance/speed

  time = (520 mi)/(130 mi/h) = 4 h

4 hours after 9 am, Kate and Will will meet. That time is 1 pm.