221.57
Explanation:
To round to the nearest tenth you would would look at the hundredths place. If it is higher than 5 you round the number in the tenth place up if it is lower than 5 you keep it the number in the tenth place the same. In this case you have 2 which is lower than 5 so you keep the 7 the same and bring everything else down.
Answer:
The probability P of a day with no perceptible earthquakes is 0.0821.
Step-by-step explanation:
We will consider that earthquakes occurring in a day is a <u>Poisson process</u>. The following Poisson probability distribution formula will be used in this question.
<u>p(x,λ) = [e^-λ (λ)ˣ]/x!</u>
where x = number of outcomes occurring
λ = mean number of occurrences
(a) So, in this question we have λ = 2.5 and we need to find the probability that x=0 (no perceptible earthquakes in a day). So,
P(X=0) = p(0,2.5) = [(e^-2.5)(2.5)⁰]/0!
= ((0.0821)*1)/1
P(X=0) = 0.0821
The probability P of a day with no perceptible earthquakes is 0.0821.
13^12 + 11^12 + 8^12 = 384 It will cost 384 dollars for all 12 uniforms
When you round you have to check the number to the right of the number you are rounding. If the number to the right is 0-4 then you keep the number the same. 5-9 the number you are rounding goes up by one. Now the 4 before the decimal point is in the ones spot. The 5 to the right of the 4 is the tenth spot and the 6 to the right of that is in the hundredth spot. so this is where we need to round. To the right of the 6 is a 4 so the number would stay the same. Now when you round you drop all the numbers after it so the number is 3184.56
