Question

What is the solubility of 618 grams of zinc chloride (ZnCl2) dissolved into 150 cm3 of water?

Answer 1

The solubility of 618 grams of Zinc chloride (ZnCl2) dissolved into 150 cm³ of water is 4120g/dm³.

Further Explanation;

Solubility

• Solubility refers to the ability of a substance called the solute to dissolve on another called the solvent.
• Solubility is measured as the maximum amount of solute that can dissolve in a solvent at a given temperature.
• It is therefore defined as the maximum amount of a solute that can dissolve in a 100g of water. It is measured in either in grams per 100 g of solvent (water) or number of moles per L of solution.

To calculate the solubility in g/100g.

• We divide the mass of the compound(solute) by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g
• Solubility = Mass of solute × 100 g/mass of solvent (water).

We are given;

Mass of solute = 618 g of ZnCl2

Mass of water = 150 cm³

Therefore;

Solubility of ZnCl2 = 618 g × 100 g/150 cm³

                               = 412 g/100 g of water

Solubility in g/dm³ we;

= 412 g ÷ 0.1 dm³

= 4120 g/dm³

Keywords: Solubility, solubility calculation, solubility in g/100g.

Learn more about:

• Solubility: brainly.com/question/12289941
• Calculation of solubility: brainly.com/question/494904
• Factors affecting solubility: brainly.com/question/12414410

Level: High school

Subject: Chemistry

Topic: Solubility

Sub-topic:  solubility of substances in water

Answer 2

Answer:

D. 4120 g/dm3

Explanation:

Given:

Mass of Zn = 618 g

Mass of water = 150 cm3

To determine:

Solubility of the given amount of Zn in water

Calculation:

Solubility is the amount of a substance that can be dissolved in a given volume.

Unit conversion:

1 cm3 = 0.001 dm3

Therefore, 150 cm3 of water is equivalent to:

$\frac{150 cm3*0.001dm3}{1cm3}=0.15dm3$

$Solubility = \frac{618g}{0.15dm3}=4120g/dm3$