A student has a rectangular block. It is 2 cm wide. 3 cm tall and 25cm long. It has a mass of 600 g. First, calculate the volume
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The value of ideal gas constant (R) in Joule is 8.314 Joule . Now the given expression is 1.00 J. g
. Where the g represent the temperature. Thus the abbreviated g must have the value 8.314 to satisfy the original value. Thus the temperature scale will be 1 kelvin = 8.314 g. Now 1 kelvin = -272.15°C or in terms of abbreviation of g we can write -272.15 °C = 8.314g, or, 1°C = (-)
g. Thus the temperature scale of the g scale is 1 kelvin (K) = 8.314g and 1°C = 0.030 g.