Y-(-1)=3(x-3)->y+1=3x-9->y=3x-10 so y=3x-10 is your new line
we can factor the whole thing:
(2sin(x) -1)(sin(x)+1) = 0.
Therefore, sin(x) = -1 and sin(x) = 1/2.
For the first one x = 3π/2 and the second is π/6 and 5π/6
So 3π/2, π/6 and 5π/6 are the solutions.
I do kind of have a problem with this because it doesn't mention if you should go over 360°. Otherwise, you have to add in an 2nπ into the equations like 3π/2 + 2nπ; 
but I don't know if that is necessary for you.
Answer:
Forces in our Universe
Step-by-step explanation:
a)
First of all we have,
and,
We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,
That is,
For this case F is a conservative field and the line integral is independent of the path. Thus, defining 
and 
. So the amount of work on the movement of the object from P1 to P2 is,
2) The gravitational force field is given by,
The maximum distance from the earth to the sun is 
km and the minimum distance is 
km. The mass values of the bodies are given by m = 
kg, M = 
kg and the constant G is 
In this way we raise the problem like this,
The standard form of the equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle, (x,y) is a point of the circle, and r is the length of the radius of the circle. When the equation of a circle is written, h,k, and r are numbers, while x and y are still variables. (x-2)^2 + (y-k)^2 = 16 is an example of a circle. The problem gives us two of the three things that a circle has, a point (5,9) and the center (-2,3). We need to find the radius in order to write the equation. We substitute -2 for h, 3 for k, 5 for x, and 9 for y to get (5 - (-2))^2 + (9 - 3)^2 = r^2 We simplify: 49 + 36 = r^2, r^2 = 85. We only need to know r^2 because the equation of a circle has r^2. We now have all the information to write the equation of a circle. (x + 2)^2 + (y - 3)^2 = 85.
a cause their really isnt any ADEF like in letters
