Question

If there are x teams in a sports​ league, and all the teams play each other​ twice, a total of​ N(x) games are​ played, where ​N(x)equalsxsquaredminusx. A softball league has 5 ​teams, each of which play the others twice. If the league pays ​$35 per​ game, how much will it cost to play the entire​ schedule?

Answer 1

Answer:

It will cost $700 to play the entire​ schedule.

Step-by-step explanation:

Given : $N(x)=x^2-x$

To Find :  A softball league has 5 ​teams, each of which play the others twice. If the league pays ​$35 per​ game, how much will it cost to play the entire​ schedule?

Solution:

Equation for total no. of games when all the teams play each other​ twice is $N(x)=x^2-x$

Now we are given that A softball league has 5 ​teams, each of which play the others twice.

So, Substitute x = 5 in the given equation

$N(x)=5^2-5$

$N(x)=20$

So, The total no. of games = 20

Cost for 1 game = $35

So, cost for 20 games = $35 \times 20 = 700$

Hence  it will cost $700 to play the entire​ schedule.