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erik [133]
3 years ago
15

. The density of gold is 19.32 g/mL. A U.S. $5.00 gold coin has a diameter of 1.62 cm and a thickness of 0.085 cm. The price of

gold is currently $53.90 per gram. What is the value of the gold in the coin. V = π r2 h.
Chemistry
1 answer:
Lostsunrise [7]3 years ago
7 0

Answer:

$182 is the value of the gold in the coin

Explanation:

Diameter is 2r, the ratio of the coin is = 1.62cm / 2 = 0.81cm

Following the formula of the volume of the coin:

V = π r² h

V = π*(0.81cm)²*0.085cm

V = 0.172cm³ = mL

As the density of the gold is 19.32g/mL, the mass of 0.1752mL of gold is:

0.1752mL * (19.32g / mL) =

3.385g is the mass of the coin

As the price of the gold is $53.90 / g, the value of the gold in the coin is:

3.385g * ($53.90 / g) =

<h3>$182 is the value of the gold in the coin</h3>

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How is stoichiometry used to calculate energy released when a mass of liquid freezes?
kati45 [8]

Answer:

D. Grams liquid x mol/g x delta Hf​reezing

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to reason that the stoichiometry used to calculate energy released when a mass of liquid freezes, involves the grams of the liquid, the molar mass of the liquid, as given in all the group choices, and the enthalpy of freezing because that is the process whereby a liquid goes solid.

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6 0
3 years ago
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Solution :

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$0.10 \ M \ AgCH_3COO$    -----     Less soluble than in pure water.

$0.10 \ M \ Na_2CrO_4$   ----- Less soluble than in pure water.

$0.10 \ M \ NH_4NO_3$   -----   Similar solubility as in the pure water

$0.10 \ M \ KCH_3COO$   -----   Similar solubility as in the pure water

The silver chromate dissociates to form :

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When 0.1 M of $AgCH_3COO^-$ is added, the equilibrium shifts towards the reverse direction due to the common ion effect of Ag^+, so the solubility of Ag_2CrO_4 decreases.

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4 0
3 years ago
Which of the following is an example of a chemical change?
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Answer:

D

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It is D because once youve put together the ingredients and baked it you can not go in and taake out every ingredient and put it back to how it was before (Please also try to help me with my question it it about scaled copies, Please and thank you!)

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allochka39001 [22]

Answer:

1.18×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms.

From the above concept, 1 mole of sodium also contains 6.02×10²³ atoms.

1 mole of sodium = 23 g.

Thus,

23 g of sodium contains 6.02×10²³ atoms.

Therefore, 4.5 g of sodium will contain = (4.5 × 6.02×10²³)/23 = 1.18×10²³ atoms.

From the above calculation,

4.5 g of sodium contains 1.18×10²³ atoms.

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