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Keith_Richards [23]
3 years ago
15

Someone please help will mark as brainliest

Chemistry
1 answer:
Inessa05 [86]3 years ago
4 0

Answer:

D water

Explanation:

sorry if im wrong bit i remeber correctñy i had this on my test

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Identify from the following list of molecules and ions which behave as Lewis acids: CO2, NH3, BCl3, Fe3+. (A) CO2 and NH3 (B) NH
allsm [11]

Answer : The correct option is, (D) CO₂, BCl₃, and Fe³⁺

Explanation :

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

(a) CO_2

It is a Lewis-acid because it can accepts electron pairs.

(b) NH_3

It is not a Lewis-acid because it can not accepts electron pairs but it is a base because it can donates and accept hydrogen ion.

(c) BCl_3

It is a Lewis-acid because it can accepts electron pairs because it has an incomplete octet and an empty 2p orbital.

(d) Fe^{3+}

It is a Lewis-acid because it can accepts electron pairs.

Hence, the ions which behave as Lewis acids are, CO₂, BCl₃, and Fe³⁺

6 0
3 years ago
Sulfuric acid in water dissociates completely into H+ and HSO4− ions. The HSO4− ion dissociates to a limited extent into H+ and
erastova [34]

Answer:

0.0010m SO₄²⁻

Explanation:

The freezing point depression due the addition of a solute into a pure solvent follows the equation:

ΔT = Kf×m×i (1)

<em>Where ΔT are °C that freezing point decreases (273.15K - 272.47K = 0.68K = 0.68°C). Kf is the constant of freezing point depression (1.86°C/m), m is molality of the solution (0.1778m) and i is Van't Hoff factor.</em>

Van't Hoff factor could be understood as  in how many one mole of the solute (sulfuric acid, H₂SO₄), is dissociated.

H₂SO₄ dissociates as follows:

H₂SO₄ → HSO₄⁻ + H⁺

HSO₄⁻ ⇄ SO₄²⁻ + H⁺

<em>Not all HSO₄⁻ dissociates.</em>

1 Mole of H₂SO₄ dissociates in 1 mole of H⁺+ 1 mole of HSO₄⁻ + X moles of   SO₄²⁻= 2 + X

Replacing in (1):

0.68°C = 1.86°C/m×0.1778m×i

2.056 = i

Moles of SO₄²⁻ are 2.056 - 2 = 0.056moles SO₄²⁻.

If 1 mole has a concentration of 0.1778m, 0.056moles are:

0.056moles ₓ (0.1778m / 1mole) =

<h3>0.0010m SO₄²⁻</h3>
8 0
3 years ago
12.5 g of copper are reacted with an excess of chlorine gas, and 25.4 g of copper(II) chloride are
Alika [10]

Answer:

Percent yield = 94.5%

Theoretical yield =  26.89 g

Explanation:

Given data:

Mass of copper = 12.5 g

Mass of copper chloride produced = 25.4 g

Theoretical yield = ?

Percent yield = ?

Solution:

Cu + Cl₂  →  CuCl₂

Number of moles of Copper:

Number of moles = mass/ molar mass

Number of moles = 12.5 g/ 63.55 g/mol

Number of moles = 0.2 mol

Now we will compare the moles of copper with copper chloride.

          Cu          :           CuCl₂

           1             :              1

          0.2          :            0.2

Theoretical yield:

Mass of copper chloride:

Mass = Number of moles × molar mass

Mass = 0.2 mol × 134.45 g/mol

Mass = 26.89 g

Percent yield:

Percent yield = Actual yield / theoretical yield  × 100

Percent yield = 25.4 g/26.89 g × 100

Percent yield = 94.5%

8 0
4 years ago
A student measures the S2- concentration in a saturated aqueous solution of iron(II) sulfide to be 2.29×10-9 M. Based on her dat
katrin2010 [14]

Answer:

Ksp FeS = 5.2441 E-18

Explanation:

  • FeS ↔ Fe2+  + S2-

         S          S           S

∴ Ksp = [Fe2+]*[S2-].....solubility product constant

∴ [S2-] = 2.29 E-9 M = S

⇒ Ksp = (S)(S) = S²

⇒ Ksp = (2.29 E-9)²

⇒ Ksp = 5.2441 E-18

8 0
3 years ago
Fusion reactions are commercially viable because they require low energies to initiate and sustain a reaction.
guajiro [1.7K]

Answer:

False.

Explanation:

Fusion reactions are not yet commercially viable because they require extremely high energies to initiate and sustain a reaction.

3 0
3 years ago
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