D=m/v d=63.5g/11.6cm3=5.47g/cm3
LiOH + H2SO4 <span>→ Li2SO4 + H2O
Balance the equation:
Reactants:
Li = 1 • 2
O = 1 • 2 + 4
H = 1 • 2+ 2
S = 1
Products:
Li = 2
O = 4 + 1 • 2
H = 2 • 2
S = 1
Balanced Equation:
</span>2LiOH + H2SO4 → Li2SO4 + 2H2O
There is 118 elements<span> in the periodic table</span>
<h3>
Answer:</h3><h3>a) 9.033 × 10²³ particles</h3><h3>b) 4.068 × 10²⁴ particles</h3><h3>c) 1.51 × 10²³ particles</h3>
Explanation:
For us to answer these questions, we have to know two formulas:
- Number of particles = moles × Avogadro's Number
- Moles = Mass ÷ Molar Mass
Therefore:
a) particles of Na = 1.50 mol × (6.022 × 10²³) particles/mol
= 9.033 × 10²³ particles
b) particles of Pb = 6.755 mol × (6.022 × 10²³) particles/mol
= 4.068 × 10²⁴ particles
c) particles of Si
= (7.02 g ÷ 28.085 g/mol) × (6.022 × 10²³) particles/mol
= 1.51 × 10²³ particles