Ans: Moles of Fe(OH)2 produced is 5.35 moles.
Given reaction:
Fe(s) + 2NiO(OH) (s) + 2H2O(l) → Fe(OH)2(s) + 2Ni(OH)2(aq)
Based on the reaction stoichiometry:
1 mole of Fe reacts with 2 moles of NiO(OH) to produce 1 mole of Fe(OH)2
It is given that there are:
5.35 moles of Fe
7.65 moles of NiO(OH)
Here the limiting reagent is Fe
Therefore, number of moles of Fe(OH)2 produced is 5.35 moles.
It has a 1:2 ratio
If you look at the start of PbO2 it does not have a number so that is the one and if you look at 2H2O that has a 2 in front so that is where you get the 1:2 ratio
Answer:
See explanation
Explanation:
The nucleophile here is CH3OH. We know that CH3OH is a good nucleophile that promotes SN2 reanction. However, (R)-6-bromo-2,6-dimethylnonane is a tertiary alkyl halide so the reaction proceeds by SN1 mechanism. This means that a racemic mixture is obtained at the end of the reaction because the attack occurs at the stereogenic carbon atom (6R) hence the product is optically inactive.
On the other hand, when (5R)-2-bromo-2,5-dimethylnonane is reacted with CH3OH, an optically active product is obtained because; though a tertiary alkyl halide and reaction occurs by SN1 mechanism, the attack does not occur at the stereogenic carbon atom (5R). Therefore, an optically active product is obtained in this case.
