The amount of heat needed to melt 423 g of water at 0°C is 141282 J
The heat required to melt water can be obtained by using the following formula:
<h3>Q = mL </h3>
Q is the heat required.
L is the latent heat of fusion (334 J/g)
m is the mass.
With the above formula, we can obtain the heat required to melt the water as illustrated below:
Mass of water (m) = 423 g
Latent heat of fusion (L) = 334 J/g
<h3>Heat (Q) required =? </h3>
Q = mL
Q = 423 × 334
<h3>Q = 141282 J</h3>
Therefore, the amount of heat needed to melt 423 g of water at 0°C is 141282 J
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And Example for Physical Property it’s : Gold Is Shiny
And Chemical and like a dry piece of paper burning
Hypothesis is your opinion/ your thinking and yes, scientists have hypothesis before they do an experiment
Hope this helps!
Answer is: B₂O₃ + Mg → B + MgO.
B₂O₃ + 3Mg → 2B + 3MgO, balanced.
B₂O₃ - diboron trioxide. White, glassy solid compound.
B - boron. Metalloid, crystalline boron is and amorphous<span> boron is a brown powder.
Mg - magnesium. S</span><span>hiny, gray and solid metal.
MgO - magnesium oxide. W</span><span>hite, </span>hygroscopic<span> solid powder.</span>
