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4 years ago

12

Is 37.508 greater than 3.758

2 answers:

insens350 [35]4 years ago

8 0

Yes it is greater. If you look at the first two digets in the front, it is 37 compared to 3.7 . 37 is obviously greater than 3.7 so 37.508 is greater than 3.758

S_A_V [24]4 years ago

6 0

Yes it is,since 37 is greater than 3

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F(x)=4x+7 Place the steps for finding f -1(x) in the correct order.

dybincka [34]

X=4x+7

X=4y+7

X-7=4y

X-7/4=y

F-1(x)=x-7/4

6 0

4 years ago

How do you convert 250% into a fraction

Ann [662]

Hello there.

Question: <span>How do you convert 250% into a fraction.

Answer: </span>Step 1: Factor both the numerator and denominator down to prime factors:
250 = 2 * 53
100 = 22 * 52
Step 2: Calculate the greatest common factor, GCF
GCF = (2 * 53; 22 * 52) = 2 * 52
Step 3: Divide both the numerator and denominator by their greatest common factor, 250/100 =
(2 * 53)/(22 * 52) =
<span>((2 * 53) : (2 * 52))</span> / <span>((22 * 52) : (2 * 52))</span> =
5/2
Ways of writing this:

<span>Positive improper fraction:
250/100 = 5/2

Mixed number (also called mixed fraction):
250/100 = 2 1/2

Decimal number:
250/100 = 2.5

In short, Your answer is<span> 5/2</span>.

Hope This Helps You!
<span>Good Luck Studying ^-^</span></span>

6 0

4 years ago

A manager records the repair cost for 4 randomly selected TVs. A sample mean of $88.46 and standard deviation of $17.20 are subs

WINSTONCH [101]

Answer:

a) The critical value is $z = 2.575$ .

b) The 99% confidence interval for the mean repair cost for the TVs is ($66.31, $110.61).

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ . This is our critical value

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

a. Find the critical value that should be used in constructing the confidence interval.

The critical value is $z = 2.575$ .

b. Construct the 99% confidence interval. Round your answer to two decimal places.

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. So, in this problem

$M = 2.575*\frac{17.20}{\sqrt{4}} = 22.15$

The lower end of the interval is the mean subtracted by M. So it is 88.46 - 22.15 = $66.31

The upper end of the interval is the mean added to M. So it is 88.46 - 22.15 = $110.61

The 99% confidence interval for the mean repair cost for the TVs is ($66.31, $110.61).

5 0

3 years ago

storchak [24]

10 ...............................

8 0

3 years ago

Find the annual interest rate.

slega [8]

The annual interest rate is 3.5%.

Solution:

Given Interest (I) = $26.25

Principal (P) = $500

Time (t) = 18 months

Rate of interest (r) = ?

Time must be in years to find the rate per annum.

1 year = 12 months

Divide the time by 12.

Time (t) = $\frac{18}{12}=\frac{3}{2}$ years

Now, find the rate of interest using simple interest formula.

<u>Simple interest formula:</u>

$$I=\frac{Prt}{100}$

$$26.25=\frac{500\times r\times \frac{3}{2} }{100}$

$$26.25\times 100 =500\times r\times \frac{3}{2}$

$$2625 =250\times r\times 3$

$$2625 =750\times r$

$$\Rightarrow r=\frac{2625}{750}$

⇒ r = 3.5%

Hence the annual interest rate is 3.5%.

8 0

4 years ago