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2 years ago

10

Convert 2 5/6 to an improper fraction

1 answer:

bearhunter [10]2 years ago

3 0

Multiply the denominator by the number in front of it and then add it to the numerator. (6•2=12+5=17). The denominator stays the same. Your answer is 17/6. Hope this helped!

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Find the distance between each pair of points. Round your answer to the nearest tenth, if necessary. Hint: Use the Pythagorean T

Paul [167]

The distance between two points on the plane is given by the formula below

$\begin{gathered} A=(x_1,y_1),B=(x_2,y_2) \\ \Rightarrow d(A,B)=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2} \end{gathered}$

Therefore, in our case,

$A=(-1,-3),B=(5,2)$

Thus,

$\begin{gathered} \Rightarrow d(A,B)=\sqrt[]{(-1-5)^2+(-3-2)^2}=\sqrt[]{6^2+5^2}=\sqrt[]{36+25}=\sqrt[]{61} \\ \Rightarrow d(A,B)=\sqrt[]{61} \end{gathered}$

Therefore, the answer is sqrt(61)

In general,

$-(-n)=n$

Remember that

$-n=(-1)\cdot n$

Therefore,

$\begin{gathered} a-(-n)=a+(-1)(-n)=a+(-1)(-1\cdot n)=a+(-1)^2\cdot n=a+1\cdot n=a+n \\ \Rightarrow a-(-n)=a+n \end{gathered}$

6 0

1 year ago

Solve and show work: <br> f(300) = 90 + 0.11x

Vinil7 [7]

300-90= 90-90 +0.11x 210=0.11x 210/.11 0.11x/0.11
1909 = x I think but Idk

6 0

3 years ago

Thank you so much for you help

ankoles [38]

Your welcome for the help

8 0

2 years ago

Lin run 5 laps around a track in 10 minutes. How many minutes per lap is that

ludmilkaskok [199]

Answer:

2min per lap

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Sin0=12/37 find tan0

alexira [117]

Answer:

$\large{ \tt{❃ \: EXPLANATION}} :$

We're provide - Sin θ = $\frac{12}{37}$ which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = $\tt{ \frac{p}{h}}$ ] . We're asked to find out tan θ ].

$\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :$

$\large{ \tt{❊ \: {h}^{2} = {p}^{2} + {b}^{2} }}$

$\large{ \tt{⇢ {p}^{2} + {b}^{2} = {h}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = {h}^{2} - {p}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = {37}^{2} - {12}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = 1369 - 144}}$

$\large{ \tt{ ⇢{b}^{2} = 1225}}$

$\large{ \tt{⇢ \: b = \sqrt{1225}}}$

$\large{ \tt{⇢ \: b = 35 \: \text {units}}}$

Now , We know - Tan θ= $\tt{ \frac{perpendicular}{base} }$ . Just plug the values :

$\large{ \tt{➝ \: Tan \: \theta = \frac{p}{b} = \boxed{ \tt{ \frac{12}{35} }}}}$

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5 0

2 years ago