The initial dimenssions of the park lot are:
length: 140 ft
width: 90 ft
initial area: 140 * 90 = 12,600 ft^2
Area increased 29% = 12,600 * 1.29 = 16,254 ft^2
width of the strips: x
New length: 140 + x
New width: 90 + x
New area: (140+x)(90+x) = 16,254
Solution of the equation:
12600 + 230x + x^2 = 16254
=> x^2 + 230x - 3654 = 0
Use the quadratic formula.
x = {-230 +/- √[ 230^2 - 4*1*(-3654) ]} / 2 =
x = 14.92
The other solution is negative so it is discarded.
Answer: 15 ft
Answer:
The minimum sample size that should be taken is 62.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
If we want to be 90% confident that the sample mean is within 1 word per minute of the true population mean, what is the minimum sample size that should be taken
This is n when 
. So
The minimum sample size that should be taken is 62.
answer:
10 packs
Step-by-step explanation:
just do 30/3 and you get the answer!!!
:)
Answer: 5 and 4
Step-by-step explanation:
Perimeter = 2 ( L + W)
18 = 2(L + W) divide through by 2
9 = L + W
9 - L = W
Area = L * W
20 = L (9 - L)
20 = 9L - L^2
L^2 - 9L + 20 = 0 factor
(L - 5) (L - 4) = 0
Set both factors to 0 and solve for L
L = 5 and L = 4
