The number of cans that would be considered lethal if 10g was lethal and there where 12oz in a can is 419 cans.
<h3>How to convert mass?</h3>
According to this question, caffeine concentration is 1.99 mg/oz.
1.99 milligrams can be converted to grams as follows:
1.99milligrams ÷ 1000 = 0.00199grams
This means that 0.00199grams per oz is the caffeine concentration.
If there were 12 oz in a can, then, 0.00199grams × 12 = 0.02388 grams in 1 can.
This means that if 10grams is considered lethal, 10grams ÷ 0.02388 grams = 419 cans would be lethal for consumption.
Therefore, the number of cans that would be considered lethal if 10g was lethal and there where 12oz in a can is 419 cans.
Learn more about conversion factor at: brainly.com/question/14479308
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A) an object with mass > 0 in a gravitational field
b) an object with an electric charge not 0 in an electric field
c) a moving object with an electric charge not 0 in a magnetic field
The concepts required to solve this problem are those related to the conservation of the angular momentum and the moment of inertia of the disk. We will begin by calculating the moment of inertia of the disc, then the moment of inertia of the disc after the two two blocks hits and sticks to the edges of the turn table. In the end we will apply the conservation theorem.
The radius is given as,

When a block falls from above and sticks to the turn table, the moment inertia of the turntable increases.
Since two blocks are stick to the turn table, the total final moment of inertia of the turntable is the sum moment of inertias of individual turntable, and two blocks.



The moment of inertia of each block is

Total moment of inertia of two block is

The final moment of inertia of the turn table is




From the conservation of the angular momentum, the initial angular momentum of the system is equal to final angular momentum of the system,
Rearrange the equation we have that




The magnitude of the turntable's angular velocity is 66.67rpm
The smaller the atom,the larger the first I.E.
Answer: The comet's average distance from the sun is 17.6AU
Explanation:
From Kepler's 3rd Law, P^2=a^3
Where P is period in years
and a is length of semi-major axis or the average distance of the comet to the sun.
Given the orbital period to be 74 years
74^2 =a^3
5476 = a^3
Cube root of 5476 =a
17.626 = a
Approximately a= 17.6 AU