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elena55 [62]
3 years ago
10

In a towns water system pressure gauges in still water at street level reads 150kpa. if a pipeline connected to the system break

s and shoots water straight up, how high above the street does the water shoot?
Physics
1 answer:
AnnZ [28]3 years ago
5 0

Answer:

The water shoots 15.31 m high above the street level.

Explanation:

The gauge pressure drives the motion of the water to whixhever height it will attain. The expression relating the gauge pressure to the height reached by the water, is

P = ρgh

P = Gauge Pressure = 150 kPa = 150,000 Pa

ρ = density of the fluid (water) = 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = Height reached by the water = ?

150,000 = 1000 × 9.8 × h

h = (150000) ÷ 9800 = 15.306 = 15.31 m

Hope this Helps!!!

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You pour 250 g of tea into a Styrofoam cup, initially at 80∘C and stir in a little sugar using a 100-g aluminum 20∘C spoon and l
jok3333 [9.3K]

To solve this problem it is necessary to apply the concepts related to the conservation of energy and heat transferred in a body.

By definition we know that the heat lost must be equal to the heat gained, ie

Q_g = Q_l

Where,

Q = Heat exchange

The heat exchange is defined as

Q = c_p m \Delta T

Where,

c_p = Specific heat

m = mass

\Delta T= Change in Temperature

Therefore replacing we have that

Q_g = Q_l

c_{p-tea} m \Delta T =  c_{p-al} m \Delta T

Replacing with our values we have that

0.25*4180*(80-T) = 0.1*900*(T-20)

11.61*(80-T) = T-20

T= \frac{948.8}{11.61}

T = 75.24\°C

Therefore the highest possible temperature of the spoon when you finally take it out of the cup is 75.24°C

3 0
3 years ago
Mr. Ben drove from Town A to Town B. For the first 3 h, he traveled at an average speed of
Vanyuwa [196]

Answer:

It’s 7 hours

Explanation:

You have to use the formula your teacher has given to you plug in the numbers then solve be sure to use a calculator made for physics it helps a lot :)

8 0
3 years ago
How can you measure the distance an object has moved?
Naily [24]

You must observe the object twice.

-- Look at it the first time, and make a mark where it is.

-- After some time has passed, look at the object again, and
make another mark at the place where it is.

-- At your convenience, take out your ruler, and measure the
distance between the two marks.

What you'll have is the object's "displacement" during that period
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8 0
3 years ago
1 Point
irakobra [83]

Answer:

SECOND LAW OF NEWTON

Explanation:

When the rocket fires the engines the gases leave at high speed and collide with the space station, transferring an impulse given by the expression

                I = F t = Δp

As we can see this expression is a form of Newton's second law

           F = m a

           a = dv / dt

           F = m dv / dt

           F dt = m dv

           p = mv

           F dt = dp

Therefore the station moves through the SECOND LAW OF NEWTON

7 0
2 years ago
What does this observation tell you about the relationship between the external force applied and the object’s acceleration (the
Dvinal [7]

Explanation:

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First, what do we mean by a change in motion? The answer is that a change in motion is equivalent to a change in velocity. A change in velocity means, by definition, that there is an acceleration. Newton’s first law says that a net external force causes a change in motion; thus, we see that a net external force causes acceleration.

3 0
2 years ago
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