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elena55 [62]
3 years ago
10

In a towns water system pressure gauges in still water at street level reads 150kpa. if a pipeline connected to the system break

s and shoots water straight up, how high above the street does the water shoot?
Physics
1 answer:
AnnZ [28]3 years ago
5 0

Answer:

The water shoots 15.31 m high above the street level.

Explanation:

The gauge pressure drives the motion of the water to whixhever height it will attain. The expression relating the gauge pressure to the height reached by the water, is

P = ρgh

P = Gauge Pressure = 150 kPa = 150,000 Pa

ρ = density of the fluid (water) = 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = Height reached by the water = ?

150,000 = 1000 × 9.8 × h

h = (150000) ÷ 9800 = 15.306 = 15.31 m

Hope this Helps!!!

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igor_vitrenko [27]

Answer:

Explanation:

potential energy of compressed spring

= 1/2 k d²

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This energy will be given to block of mass of 1.2 kg in the form of kinetic energy .

Kinetic energy after crossing the rough patch

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= 3.174 J

Loss of energy

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This loss is due to negative work done by frictional force

work done by friction = friction force x width of patch

= μmg d ,   μ = coefficient of friction , m is mass of block , d is width of patch

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365 d² - 3.174   = .2587

365 d² = 3.4327

d² = 3.4327 / 365

= .0094

d = .097 m

= 9.7 cm

If friction increases , loss of energy increases . so to achieve same kinetic energy , d will have to be increased so that initial energy increases so compensate increased loss .

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3 years ago
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Answer:

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The example can be

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