Question

In a towns water system pressure gauges in still water at street level reads 150kpa. if a pipeline connected to the system breaks and shoots water straight up, how high above the street does the water shoot?

Answer 1

Answer:

The water shoots 15.31 m high above the street level.

Explanation:

The gauge pressure drives the motion of the water to whixhever height it will attain. The expression relating the gauge pressure to the height reached by the water, is

P = ρgh

P = Gauge Pressure = 150 kPa = 150,000 Pa

ρ = density of the fluid (water) = 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = Height reached by the water = ?

150,000 = 1000 × 9.8 × h

h = (150000) ÷ 9800 = 15.306 = 15.31 m

Hope this Helps!!!