In order to solve this problem, there are two equations that you need to know to solve this problem and pretty much all of kinematics. The first is that d=0.5at^2 (d=vertical distance, a=acceleration due to gravity and t=time). The second is vf-vi=at (vf=final velocity, vi=initial velocity, a=acceleration due to gravity, t=time). So to find the time that the ball traveled, isolate the t-variable from the d=0.5at^2. Isolate the t and the equation now becomes
![\sqrt{(2d)/a}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%282d%29%2Fa%7D%20)
. Solving the equation where d=8 and a=9.8 makes the time
![\sqrt{(2*8)/9.8}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%282%2A8%29%2F9.8%7D%20)
=1.355 seconds. With the second equation, the vi=0 m/s, the vf is unknown, a=9.8 m/s^2 and t=1.355 sec. Substitute all these values into the equation vf-vi=at, this makes it vf-0=9.8(1.355). This means that the vf=13.28 m/s.