Answer:
v = 12.52 [m/s]
Explanation:
To solve this problem we must use the energy conservation theorem. Which tells us that potential energy is transformed into kinetic energy or vice versa. This is more clearly as the potential energy decreases the kinetic energy increases.
Ep = Ek
where:
Ep = potential energy [J] (units of joules]
Ek = kinetic energy [J]
Ep = m*g*h
where:
m = mass of the rock = 45 [g] = 0.045 [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = (20 - 12) = 8 [m]
Ek = 0.5*m*v²
where:
v = velocity [m/s]
The reference level of potential energy is taken as the ground level, at this level the potential energy is zero, i.e. all potential energy has been transformed into kinetic energy. In such a way that when the Rock has fallen 12 [m] it is located 8 [m] from the ground level.
m*g*h = 0.5*m*v²
v² = (g*h)/0.5
v = √(9.81*8)/0.5
v = 12.52 [m/s]
Bases:
x- middle strength
y- strongest base
z- weakest base
The bases and conjugate acids have an inverse strength. The stronger the conjugate base, the weaker its conjugate acid.
I am considering two scenarios:
Scenario 1:
y- strongest base ; hy - weakest conjugate acid
x- middle base ; hx - middle conjugate acid
z- weakest base ; hz - strongest conjugate acid
hz → hx → hy
Scenario 2:
y-strongest base ; hy - weakest conjugate acid
x-middle base ; hx - strongest conjugate acid
z-weakest base ; hz - middle conjugate acid
hx → hz → hy
Answer:
This is as a result that about the central axis a collapsed hollow cone is equivalent to a uniform disc
Explanation:
The integration of the differential mass of the hollow right circular cone yields
and for a uniform disc
I = 1/2πρtr⁴ = 1/2Mr².
When oxygen reacts with magnesium thenMgO3 is formed.
Mg +O2----> MgO3
