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Finger [1]
3 years ago
7

5 b. What is the molecular shape of the molecule? (3 points)

Physics
2 answers:
Llana [10]3 years ago
8 0

Answer:

tetrahedral shape.

Explanation:

Aleksandr-060686 [28]3 years ago
8 0

Answer:

Molecular Geometries. The VSEPR theory describes five main shapes of simple molecules: linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral. Apply the VSEPR model to determine the geometry of molecules where the central atom contains one or more lone pairs of electrons.

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The answer is b because ya its b
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Lindsay is planning a flight from St. Catherines to Hamilton, which lies due west of St. Catharines.
Schach [20]

Lindsay should fly the plane in the direction [W 12.5° S] to get Hamilton.

Using Sine rule to solve this question

Sine rule => SinA/a = SinB/b = SinC/c = constant

The magnitude of wind is 50 with an angle of 60 degrees.

The magnitude of plane is 200 and the angle at which it should fly is unknown and should be θ.

One side is 50 km/hr at an angle of 60 degrees.

sin 60°/200 = sin θ / 50

50 × sin 60° = 200 × sin θ

√3/2 = 4 × sin θ

√3/8 = sin θ

sin θ = 0.2165

θ = sin⁻¹(0.2165)

θ = 12.5°

So Lindsay have to fly the plane in the direction of [W 12.5° S].

Learn more about Sine Rule here:

brainly.com/question/27174058

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3 0
2 years ago
Savanna regions developed during the Triassic period.
stich3 [128]
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5 0
1 year ago
A branch of mechanics dealing with the mathematical methods of describing motion
alexdok [17]
Kinematics is the branch of Physics that deals with
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3 0
4 years ago
Assume that the mass has been moving along its circular path for some time. You start timing its motion with a stopwatch when it
lesya692 [45]

Answer:

v = R\omega(-sin\omega t \hat i + cos\omega t \hat j)

Explanation:

As we know that the mass is revolving with constant angular speed in the circle of radius R

So we will have

\theta = \omega t

now the position vector at a given time is

r = Rcos\theta \hat i + R sin\theta \hat j

now the linear velocity is given as

v = \frac{dr}{dt}

v = (-R sin\theta \hat i + R cos\theta \hat j)\frac{d\theta}{dt}

v = R\omega(-sin\omega t \hat i + cos\omega t \hat j)

6 0
3 years ago
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