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3 years ago

How does a digit in the ten thousands place compare to a digit in the thousands place?

Mathematics

1 answer:

Lapatulllka [165]3 years ago

7 0

I think you mean ten thousandths place which would be like this, the ten thousand would be ten thousand times BIGGER than one, while the ten thousandth would be ten thousand times SMALLER than one

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How do you write 2x-3y=-15 In slope intercept form?

Vadim26 [7]

First, you subtract 2x on both sides
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divided on both sides by -3
$y = \frac{ - 2}{ - 3} x - \frac{15}{ - 3}$

$y = \frac{2}{3} x + 5$

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3 years ago

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Galina-37 [17]

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Step-by-step explanation:

Since the cost for border paper is given in terms of feet and the dimensions of the gym are given in meters, we want to convert them to the same unit. Let's choose to convert feet to meters since that would be only one conversion:

$15\:\mathrm{ft}=4.572\:\mathrm{m}$

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3 years ago

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kolbaska11 [484]

Answer: $1,462.50

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A conservative estimate of the number of stars in the universe is 6 x 10^22. The average human can see about 3,000 stars at nigh

Ilia_Sergeevich [38]

$2 \times 10^{19}$ times more stars are there in universe compared to human eye can see

<h3><u>Solution:</u></h3>

Given that, conservative estimate of the number of stars in the universe is $6 \times 10^{22}$

The average human can see about 3,000 stars at night with only their eyes

To find: Number of times more stars are there in the universe, compared to the stars a human can see

Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see

Then from given statement,

$\text{Stars in universe} = x \times \text{ number of stars human can see}$

<em><u>Substituting given values we get,</u></em>

$6 \times 10^{22} = x \times 3000\\\\x = \frac{6 \times 10^{22}}{3000}\\\\x = \frac{6 \times 10^{22}}{3 \times 10^3}\\\\x = 2 \times 10^{22-3}\\\\x = 2 \times 10^{19}$

Thus $2 \times 10^{19}$ times more stars are there in universe compared to human eye can see

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4 years ago