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Murrr4er [49]
3 years ago
5

How does a digit in the ten thousands place compare to a digit in the thousands place?

Mathematics
1 answer:
Lapatulllka [165]3 years ago
7 0
I think you mean ten thousandths place which would be like this, the ten thousand would be ten thousand times BIGGER than one, while the ten thousandth would be ten thousand times SMALLER than one

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If someone could help me with this that would be great!!! TYSM
likoan [24]

Answer:

1005 ft squared (B)

Step-by-step explanation:

The far left area:

30*15=450

The middle area:

-Since there is an eight feet being subtracted it is:

22*15=330

The last side:

-Since there is two 15's at the bottom we must subtract 30 from 45:

15*30*1/2=225

Add the area together:

450+330+225=1005

1005 ft squared

3 0
3 years ago
Read 2 more answers
¿Qué es 1/3 x5 / 6? ¿Qué es 2/5 x 3/7?​
Talja [164]

Answer:divicionsumrestnwufoifriuwhsih

Step-by-step explanation:

7 0
2 years ago
What is the solution of the equation? w - 2 = -3
Sophie [7]
W - 2 = -3....add 2 to both sides
w - 2 + 2 = -3 + 2...simplify
w = -1 <== ur solution
3 0
3 years ago
In order to ensure efficient usage of a server, it is necessary to estimate the mean number
juin [17]

Answer:

a. [36.19;39.21]

b. Reject the null hypothesis. The population mean of users that are connected at the same time is greater than 35.

Step-by-step explanation:

Hello!

Your study variable is,

X: "number of users of one server at a time"

The objective is to estimate the mean, for this, a sample of n=100 times was taken and the standard deviation S= 9.2 and the sample mean is X[bar]= 37.7 were calculated.

You need to study the population mean, for this you need your variable to have at least normal distribution. Since you don't have information about its distribution, but the sample is big enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample mean X[bar] to normal:

X[bar]≈N(μ;σ²/n)

a. With this approximation, you can construct the 90% Confidence Interval using the approximate Z

[X[bar] ± Z_{1-\alpha /2} * S/√n]

Z_{1-\alpha /2} = Z_{0.95} = 1.64

[37.7± 1.64* 9.2/√100]

[36.19;39.21]

b. You need to test if the population mean is greater than 35 with a level of significance of 1%.

The hypothesis is:

H₀: μ ≤ 35

H₁: μ > 35

α: 0.01

This is a one-tailed test so you have only one critical level (right tail):

Z_{1\alpha } = Z_{0.99} = 2.33

This means that if the value of the calculated statistic is equal or greater than 2.33 you will reject the null Hypothesis.

If the value is less than 2.33 you will support the null hypothesis.

The statistic is:

Z=<u> X[bar] - μ </u>= <u> 37.7 - 35 </u> = 2.93

       S/√n           9.2/10

The value 2.93 > 2.33, so you reject the null hypothesis. This means that the population mean of users that are connected at the same time is greater than 35.

<u><em>Note: </em></u><em>To make the decision using the interval calculated on a), the hypothesis should have been two-tailed and the confidence and significance levels complementary.</em>

I hope it helps!

7 0
3 years ago
Here is a list of ages (years) of children in a room: 5, 8, 5, 6, 8, 3, 6 State the median.
Ierofanga [76]

Answer:

6

Step-by-step explanation:

The median of a list of numbers is the number found in the "middle" of all the numbers. What this means is that it has the same amount of numbers larger and smaller than it in the list. To find the median, we first have to organize the list from least to greatest. Doing this, we get 3, 5, 5, 6, 6, 8, 8.

Now that we have the list, we can find the "middle number" by taking off numbers the highest number then the lowest number. Doing this we get

3, 5, 5, 6, 6, 8, 8

5, 5, 6, 6, 8

5, 6, 6

6

This means our median is 6.

7 0
3 years ago
Read 2 more answers
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