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Veseljchak [2.6K]
3 years ago
10

Please answer plzzzzzzzzzzz

Mathematics
2 answers:
Anettt [7]3 years ago
7 0

Answer:

543

Step-by-step explanation:

Iteru [2.4K]3 years ago
7 0
If this is long division then the answer should be 543

hope this helps!
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draw three rectangles.Then draw to show halves,thirds,and fourths. Write about each whole that you have drawn
Yuri [45]
Draw a rectangle, draw a line in middle. This is a halve. 
<span>Draw another rectangle, draw two lines. This is thirds.</span>
<span>Draw another rectangle, draw two lines but in a "+" type of way.. This is fourths.</span>

6 0
3 years ago
A fair die is cast four times. Calculate
Anestetic [448]

Answer:

0.1319 or 13.2%

Step-by-step explanation:

You can solve this using the binomial probability formula.

The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.

Then, we can set the equation as follows:

P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k)

n=4, x=2, k=2

when x=2  (4 2)(1/6)^2(5/6)^4-2 = 0.1157

when x=3  (4 3)(1/6)^3(5/6)^4-3 = 0.0154

when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008

Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)

4 0
3 years ago
4/16 in the lowest terms
miskamm [114]

Answer:

1/4

Step-by-step explanation:

The answer is 1/4 because 4 is the greatest common factor (GCF) of both numbers. So you divide both numbers by 4.

4 ÷ 4 = 1

16 ÷ 4 = 4

Therefore, the answer is 1/4.

6 0
3 years ago
Read 2 more answers
Find the gcf of 200 and 72
Aleks04 [339]

To get the Greates Common Factor (GCF) of 72 and 200 we need to factor each value first and then we choose all the copies of factors and multiply them:

<span><span>72:   22233  </span><span>200:   222  55</span><span>GCF:   222    </span></span>

The Greatest Common Factor (GCF) is:   2 x 2 x 2 = 8

Answer: 8
3 0
3 years ago
Which table shows y as a function of x
ANTONII [103]
The answer should be C :) in order for there to be a function, first rule is the x number cannot repeat
3 0
3 years ago
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