Answer:
ok
Step-by-step explanation:
Answer:
The percent of the parts are expected to fail before the 2100 hours is 0.15.
Step-by-step explanation:
Given :Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 hours.
To Find : If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?.
Solution:
We will use z score formula
Mean value =
Standard deviation =
We are supposed to find If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?
So we are supposed to find P(z<2100)
so, x = 2100
Substitute the values in the formula
Now to find P(z<2100) we will use z table
At z = −2.96 the value is 0.0015
So, In percent =
Hence The percent of the parts are expected to fail before the 2100 hours is 0.15.
X+yz : is the answer to your question.
Multiply both sides by 7/5.
Answer:
5x-10x+100 or a simplified version: -5x+100 where x is the number of shirts
Step-by-step explanation:
5x is for every shirt they have to pay for and it adds to the cost
-10x is for every shirt they sell which decreases the total cost
100 is for the upfront cost of having the shirts professionally designed
hope this helped and if i misunderstood something lmk so i can change it :))