using PV=mRT/Mr
V=(4.9×8.31×(273+20))/(24.3×101.5×10^3)
=4.84×10^-3 m^3
=4.84×10^6 mm^3
Answer:
<h2>14.71 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula
volume = final volume of water - initial volume of water
volume = 36.5 - 31.4 = 5.1 mL
But
1 mL = 1 cm³
5.1 mL = 5.1 cm³
From the question we have
We have the final answer as
<h3>14.71 g/cm³</h3>
Hope this helps you
Answer:
Specific gravity is the density of asubstance divided by the density of water. Since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density(but without any units).
Answer:
100 grams of C-14 decays to 25 grams in 11,460 years.
The C-14 isotope is only useful for dating fossils up to about 50,000 years old
If an ancient bone contains 6.25% of its original carbon, then the bone must be 22,920 years old.
Explanation:
We already know that the half life of C-14 is 5,730 years. After the first half life, we have 50 grams remaining. This takes 5,730 years. After the second half life (11,460 years now gone) we have 25 grams of C-14 left.
If a fossil material is older than 50,000 years an undetectable amount of 14C is left in the sample hence Carbon-14 is no longer suitable for dating the sample.
From;
0.693/5730 = 2.303/t log (No/0.0625No)
Where;
t = time taken and No = initial amount of C-14
0.693/5730= 2.77/t
t = 22,920 years
