x 0,025
HCl+KOH--> KCl + H2O
1 1
c=1M
V=25ml=0,025l ( you need the volume to be in l)
c = n/V
n=c*V
n=1*0,025=0,025 m KOH
x=0,025m
c=1 M
V=n/c
V=0,025/1=0,025l=25ml HCl
Answer is: a. Mg + 2HCl → H₂ + MgCl₂.
Reduction hald reaction: 2H⁺ + 2e⁻→ H₂.<span>
Oxidation half reaction: Mg</span>⁰ → Mg²⁺ + 2e⁻.
In this chemical reaction, magnesium lost two electrons (oxidation, change oxidation number from 0 to +2) and hydrogen gain that two electrons (reduction, change oxidation number from +1 to 0).
Answer:
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178.55g of H_2O are produced. When you find the molecular mass of NH_3 and O_2 and multiply them by their coefficients, you get 245.15. The law of conservation of mass states that mass can’t be created or destroyed, so this mass is the same for both the reactants and products. 245.15-66.60= 178.55. Hope this helps!
No he does not
Hopes it helped
