Answer:
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Explanation:
Yes these methods are only used in biology, chemistry, physics, geology and physcology.... They can't be used in maths or other subject, as it is said SCIENCE IS SCIENCE!
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Answer:
Explanation:
We have two pressures, two temperatures, and one volume.
This looks like a question in which we can use the Combined Gas Law to calculate the volume.
Data:
Calculation:
The combustion reaction of propane would be expressed as:
C3H8 + 5O2 = 3CO2 + 4H2O
To determine the mass of water that is produced from the given amount of propane, we use the mass of propane and the relation of the substances from the balanced reaction. We do as follows:
moles propane = 22 g C3H8 ( 1 mol / 44.1 g ) = 0.50 mol C3H8
moles H2O = 0.50 mol C3H8 ( 4 mol H2O / 1 mol C3H8) = 2 mol H2O
mass H2O = 2 mol H2O ( 18.02 g / 1 mol ) = 36.04 g H2O
Therefore, the mass of water that is produced from 22 grams of propane would be 36.04 g.
