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lbvjy [14]
3 years ago
8

How many atoms are in 4 moles of oxygen?

Chemistry
1 answer:
Paha777 [63]3 years ago
5 0

Answer:

There are 6.022 × 10 23 O atoms in a mole of O atoms. There are 6.022 × 10 23 O 2 molecules in a mole of . Since you have 2 oxygen atoms in one molecule, there are 2 × 6.022 × 10 23 O atoms in a mole of . A 'mole' is not short for a 'molecule

Explanation:

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What is the difference between a halogen and a halide?<br><br> need help urgently!
lina2011 [118]

Answer:

In context|chemistry|lang=en terms the difference between halogen and halide. is that halogen is (chemistry) any element of group 7, ie fluorine, chlorine, bromine, iodine and astatine, which form a salt by direct union with a metal while halide is (chemistry) a salt of any halogen acid.

Explanation:

5 0
3 years ago
Read 2 more answers
4. Calorimetry can be used to determine the specific heat capacity of different substances (not just metals). Using the online c
olya-2409 [2.1K]

Answer:

the specific heat capacity of ethanol is 2.4608 J/g°C

The variation in the final temperature is due to the rate of heat lost. Calorimeters do not dissipate or absorb energy

Explanation:

the solution is in the attached Word file

Download docx
8 0
2 years ago
If the density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 according
Svetradugi [14.3K]

Answer:

9.94 mL, the volume of ethanol needed

Explanation:

The reaction is:

C₂H₅OH(l) + 3 O₂(g) → 2 CO₂(g) + 3 H₂O(l)

We convert the mass of the formed product to moles:

15 g . 1mol / 44g = 0.341 moles

2 moles of dioxide are produced by 1 mol of ethanol, in order to stoichiometry.

Therefore, 0.341 moles of CO₂ must be produced by (0.341. 1) / 2 = 0.1705 moles of alcohol.

We convert the moles to mass, and then, the mass to volume by the use of density.

0.1705 mol . 46 g / 1 mol = 7.84 g of ethanol

Ethanol density = Ethanol mass /Ethanol volume

Ethanol volume = Ethanol mass /Ethanol density → 7.84 g /0.789 g/mL =

9.94 mL

7 0
2 years ago
Read 2 more answers
4. A salvage operator recovered coins believed to be gold. A sample weighed 385.000g and has a volume of 20.0mL. Were the coins
aleksley [76]

Answer:

Gold

Explanation:

We are given that

Mass of sample ,m=385 g

Volume ,V=20mL

We have to find the coin is gold or yellow brass.

We know that

Density=\frac{Mass}{volume}

Using the formula

Density=\frac{385}{20}g/mL

Density=19.25g/mL

Density\approx 19.3g/mL

Density of coin=19.3g/mL

Density of gold=19.3g/mL

Hence, the coin is gold.

5 0
2 years ago
Pls pls answer questions for chem final within 45 mins i will give brainliest
Setler79 [48]
#7 is D because you move the decimal 4 places
7 0
2 years ago
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