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Leno4ka [110]
3 years ago
5

A rock weighing 75.0g is placed in a graduated cylinder displacing the volume from 31.4 ml to 36.5ml. What is the density of the

rock in grams /cubic centimeter.
Chemistry
1 answer:
denis-greek [22]3 years ago
8 0

Answer:

<h2>14.71 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

volume = final volume of water - initial volume of water

volume = 36.5 - 31.4 = 5.1 mL

But

1 mL = 1 cm³

5.1 mL = 5.1 cm³

From the question we have

density =  \frac{75}{5.1}  \\  = 14.705882..

We have the final answer as

<h3>14.71 g/cm³</h3>

Hope this helps you

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PLS HELP ASAP!!!! Describe metallic bonds, include an explanation of their valence electrons. How this related to the properties
Aloiza [94]

If you look it up it will give you plenty of information. This is what I found:

The valence electrons of metals move freely in this way because metals have relatively low electronegativity, or attraction to electrons. The positive metal ions form a lattice-like structure held together by all the metallic bonds. ... When nonmetals bond together, the atoms share valence electrons and do not become ions

https://www.ck12.org/c/physical-science/metallic-bond/lesson/Metallic-Bonding-MS-PS/

5 0
3 years ago
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lana [24]

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Explanation:

8 0
3 years ago
216 J of energy is required to raise the temperature of a piece of aluminum from 15.0º C to to 35º C.
ddd [48]

Answer: 12g

Explanation:

The amount of energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 216 joules

Mass of aluminium = ? (let unknown value be Z)

C = 0.90 JºC-1g-1

Φ = (Final temperature - Initial temperature)

= 35°C - 15°C = 20°C

Then, Q = MCΦ

216 J = Z x 0.90 JºC-1g-1 x 20°C

216 J = Z x 18 J°g-1

Z = (216J/18 J°g-1)

Z = 12g

Thus, the mass of the aluminium is 12grams

8 0
4 years ago
The gauge pressure inside a vessel is ‐40kPa, at an elevation of 5000m. a) What is the absolute pressure? b) At this elevation,
hoa [83]

Answer:

a) Pabs = 48960 KPa

b) T = 433.332 °C

Explanation:

  • Pabs = Pgauge + d*g* h

∴ d = 1000 Kg/m³

∴ g = 9.8 m/s²

∴ h = 5000 m

∴ P gauge = - 40 KPa * ( 1000 Pa / KPa ) = - 40000 Pa; Pa≡Kg/m*s²

⇒ Pabs = - 40000 Kg/ms² + ( 1000 Kg/m³ * 9.8 m/s² * 5000 m )

⇒ Pabs = 48960000 Pa = 48960 KPa

a) at that height and pressure, we find the temperature at which the water boils by means of an almost-exponential graph which has the following equation:

P(T) = 0.61094 exp ( 17.625*T / ( T + 243.04 ))......P (KPa) ∧ T (°C)....from literature

∴ P = 48960 KPa

⇒ ( 48960 KPa / 0.61094 ) = exp ( 17.625T / (T+ 243.04))

⇒ 80138.803 = exp ( 17.625T / ( T + 243.04))

⇒ Ln ( 80138.803) = 17.625T / ( T + 243.04))

⇒ 11.292 * ( T + 243.04 ) = 17.625T

⇒ 11.292T + 2744.289 = 17.625T

⇒ 2744.289 = 17.625T - 11.292T

⇒ 2744.289 = 6.333T

⇒ T = 433.332 °C

3 0
3 years ago
When electrons are added to the outermost shell of a carbon atom, it forms
jenyasd209 [6]
I believe it forms an anion that has a larger radius.
3 0
3 years ago
Read 2 more answers
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