Answer:
5
Explanation:
They have 5 in common but different x
<u>Given:</u>
H2(g) + Cl2 (g) → 2HCl (g)
<u>To determine:</u>
The enthalpy of the reaction and whether it is endo or exothermic
<u>Explanation:</u>
Enthalpy of a reaction is given by the difference between the enthalpy of formation of reactants and products
ΔH = ∑nHf (products) - ∑nHf (reactants)
= [2Hf(HCl)] - [Hf(H2) + Hf(Cl2)] = 2 (-92.3) kJ = - 184.6 kJ
Since the reaction enthalpy is negative, the reaction is exothermic
<u>Ans:</u> The enthalpy of reaction is -184. kJ and the reaction is exothermic
Hello!
The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.
We have the following data:
mo (initial mass) = 53.3 mg
m (final mass after time T) = ? (in mg)
x (number of periods elapsed) = ?
P (Half-life) = 10.0 minutes
T (Elapsed time for sample reduction) = 25.9 minutes
Let's find the number of periods elapsed (x), let us see:
![T = x*P](https://tex.z-dn.net/?f=%20T%20%3D%20x%2AP%20)
![25.9 = x*10.0](https://tex.z-dn.net/?f=%2025.9%20%3D%20x%2A10.0%20)
![25.9 = 10.0\:x](https://tex.z-dn.net/?f=%2025.9%20%3D%2010.0%5C%3Ax%20)
![10.0\:x = 25.9](https://tex.z-dn.net/?f=%2010.0%5C%3Ax%20%3D%2025.9%20)
![x = \dfrac{25.9}{10.0}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cdfrac%7B25.9%7D%7B10.0%7D%20%20)
![\boxed{x = 2.59}](https://tex.z-dn.net/?f=%20%5Cboxed%7Bx%20%3D%202.59%7D%20)
Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:
![m = \dfrac{m_o}{2^x}](https://tex.z-dn.net/?f=%20m%20%3D%20%20%5Cdfrac%7Bm_o%7D%7B2%5Ex%7D%20%20)
![m = \dfrac{53.3}{2^{2.59}}](https://tex.z-dn.net/?f=%20m%20%3D%20%20%5Cdfrac%7B53.3%7D%7B2%5E%7B2.59%7D%7D%20%20)
![m \approx \dfrac{53.3}{6.021}](https://tex.z-dn.net/?f=%20m%20%5Capprox%20%5Cdfrac%7B53.3%7D%7B6.021%7D%20%20)
![\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7Bm%20%5Capprox%208.85%5C%3Amg%7D%7D%5Cend%7Barray%7D%7D%5Cqquad%5Ccheckmark%20)
I Hope this helps, greetings ... DexteR! =)
The hydrogen bonding in H₂O is stronger than that of HF
Explanation:
Hydrogen bonds are special dipole-dipole attraction in which electrostatic attraction is established between hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.
- The strength of hydrogen bonds depends on the how electronegative an atom is.
- Electronegativity refers to the tendency of an atom to gain electrons.
- The higher the value, the higher the tendency.
- This why oxygen with a higher electronegativity will form a stronger hydrogen bond with hydrogen compared to fluorine.
Learn more:
hydrogen bond brainly.com/question/12408823
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