Answer:
{x,y}={21,41}
Step-by-step explanation:
Step by Step Solution:
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System of Linear Equations entered :
[1] 4x - 2y = 2
[2] 3x - 2y = -19
Graphic Representation of the Equations :
-2y + 4x = 2 -2y + 3x = -19
Solve by Substitution :
// Solve equation [2] for the variable x
[2] 3x = 2y - 19
[2] x = 2y/3 - 19/3
// Plug this in for variable x in equation [1]
[1] 4•(2y/3-19/3) - 2y = 2
[1] 2y/3 = 82/3
[1] 2y = 82
// Solve equation [1] for the variable y
[1] 2y = 82
[1] y = 41
// By now we know this much :
x = 2y/3-19/3
y = 41
// Use the y value to solve for x
x = (2/3)(41)-19/3 = 21
Solution :
{x,y} = {21,41}
Product means multiply
product of q and 5 is 5 times q or 5q
divided by 2 so (5q)/2
Answer: 
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Work Shown:
Part 1

Part 2

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Explanations:
- There are quite a bit of steps. I decided to break things into two parts.
- The goal is to get x all by itself on its own side, which is why I subtracted (x-n)/n from both sides in part 1, step 2. I also subtracted p from both sides.
- Afterward, I gave each fraction the LCD mn. I multiplied top and bottom of the first fraction by n/n. I did a similar operation to the second fraction, but with m instead.
- From there, we distribute and simplify. The mn terms cancel on the left side numerator (second step of part 2).
- The n≠m is there to prevent the denominator (n-m) from being zero. We cannot divide by zero.
- If the formulas don't properly display, then you might have to refresh the page.
Answer: The first option is correct.
Explanation:
The given piecewise function is,

From the piecewise function we can say that if x<0, then

If
, then

Since the f(x) is defined for x<0 and
, therefore the function f(x) is not defined for
.
In the graph 2, 3 and 4 for each value of x there exist a unique value of y, therefore the function is defined for all values of x, which is not true according to the given piecewise function.
Only in figure the value of y not exist when x lies between 0 to 2, including 0. It means the function is not defined for
, hence the first option is correct.
A larger interval is wider than a smaller interval.