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3 years ago

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Which is the equation of a trend line that passes through the points (3, 95) and (11, 12)? Round values to the nearest ten-thous

andths.

2 answers:

umka2103 [35]3 years ago

7 0

The answer is y=-83/8+43

gayaneshka [121]3 years ago

5 0

Step 1

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

$A(3,95)\ B(11,12)$

Substitute the values

$m=\frac{12-95}{11-3}$

$m=\frac{-83}{8}$

$m=-\frac{83}{8}$

Step 2

Find the equation of the line in point-slope form

$y-y1=m(x-x1)$

In this problem we have

$(x1,y1)=B(11,12)$

$m=-\frac{83}{8}$

substitute

$y-12=-\frac{83}{8}(x-11)$

$y=-\frac{83}{8}x+\frac{83}{8}11+12$

$y=-10.375x+126.125$

therefore

<u>the answer is</u>

$y=-10.375x+126.125$

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I hope it helps you!

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3 years ago