Question

Which is the equation of a trend line that passes through the points (3, 95) and (11, 12)? Round values to the nearest ten-thousandths.

Answer 1

The answer is y=-83/8+43

Answer 2

Step 1

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

$A(3,95)\ B(11,12)$

Substitute the values

$m=\frac{12-95}{11-3}$

$m=\frac{-83}{8}$

$m=-\frac{83}{8}$

Step 2

Find the equation of the line in point-slope form

$y-y1=m(x-x1)$

In this problem we have

$(x1,y1)=B(11,12)$

$m=-\frac{83}{8}$

substitute

$y-12=-\frac{83}{8}(x-11)$

$y=-\frac{83}{8}x+\frac{83}{8}11+12$

$y=-10.375x+126.125$

therefore

the answer is

$y=-10.375x+126.125$