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Gnom [1K]
2 years ago
11

What are the three major branches of natural science?

Chemistry
1 answer:
ArbitrLikvidat [17]2 years ago
4 0

Explanation:

<h2>The three major branches of natural science are</h2><h2>1.Physical,the study of universe.</h2><h2>2.Chemistry,the study of matter.</h2><h2>3.Biology,the study of life and living or organisms.</h2><h2 /><h2>have a good day.</h2><h2>I hope this answer can help you</h2>
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When Niels Bohr refined the model of an atom,what new idea did he include?
pshichka [43]

Answer:

Niels Bohr, refined the model of an atom by proposing a quantized shell structure atomic model in order to describe how the electrons are able to maintain stable orbits around the nucleus

Based on the predictions of classical mechanics the electron motion of the Rutherford model was unstable as the electrons where expected to have lost some energy during motion and thus having to come rest in the nucleus

According to the modification by Neils Bohr in 1913, electrons move in  shells or orbits of fixed energy and emission of electromagnetic radiation takes place only when electrons changes the orbit in which they move

Explanation:

5 0
3 years ago
175 mL of a 1.6 M solution of KCl is diluted to a new volume of 1.0 L. What is the new concentration of the solution?
kupik [55]

Answer:

b. .28 M KCI

Explanation:

Use the dilution formula.

C₁V₁ = C₂V₂

C₂ = C₁V₁/V₂

C₂ = 1.6*0.175 / 1.0

C₂ = 0.28

6 0
3 years ago
How many grams of magnesium would contain the same number of atoms as 26.982 grams of aluminum?
vlabodo [156]
Three elements that are likely to have similar chemical and physical properties are
5 0
3 years ago
What is half of 1 and 1/3 cups of semisweet chocolate?
Marina86 [1]

Answer:

2/3 cup of semisweet chocolate

4 0
4 years ago
One mole of an ideal gas is contained in a cylinder with a movable piston. The temperature is constant at 77°C. Weights are remo
frozen [14]

Answer:

The total work is 4957.45J

Explanation:

For an ideal gas, at constant temperature the definition of work (W) is

W = - P.dV = - n.R.T \int\limits^i_f {\frac{dV}{V} \\W = - n.R.T. Ln (\frac{V_{f}}{V_{I}})\\W = - n.R.T. Ln (\frac{P_{i}}{P_{f}})

where P is the pressure, V the volume, n the moles number, T the temperature and R the gas constant.

To solve the problem is necessary to replace the two steps in the equation

Stape 1: n  = 1 mol, R = 0.082atm.L/K.mol, T = 77ºC = 350K, Pi = 5.50atm and Pf = 2.43atm.

W_{1} = - 1molx0.082\frac{atm.L}{K.mol}x350KxLn (\frac{5.50atm}{2.43atm}) = 23.44atm.Lx101.325\frac{J}{atm.L} =2375.44J

Stape 2: n  = 1 mol, R = 0.082atm.L/K.mol, T = 77ºC = 350K, Pi = 2.43atm and Pf = 1.00atm.

W_{2} = - 1molx0.082\frac{atm.L}{K.mol}x350KxLn (\frac{2.43atm}{1.00atm}) = 25.48atm.Lx101.325\frac{J}{atm.L} =2582.01J

The total work is the sum of the two steps

W = W_{1} + W_{2} = 2375.44J + 2582.01J = 4957.45J

4 0
3 years ago
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