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rjkz [21]
3 years ago
9

Factor the quadratic expression

Mathematics
1 answer:
Ber [7]3 years ago
3 0
(x - 6)(x - 2) the answer to the question

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The made 9 pounds of fudge . The fudge was separated into 3/4 pound blocks . They sell each block for $6.50 .if they sell all th
Flauer [41]
Number 16, he put 1/2 of his money into his savings and took the rest to spend. So fraction of his amusement park money he spent on rides and popcorn is (1/5 + 3/4) x 1/2 = 19/40 <=> A

Each 3/4 pound block for $6.50. So each pound block will be $6.50 x 4/3 = 26/3. They have 9 pounds of fudge, money they will make is 26/3 x 9 = $78
3 0
3 years ago
For the following right triangles:
CaHeK987 [17]

Let us first define Hypotenuse Leg (HL) congruence theorem:

<em>If the hypotenuse and one leg of a right angle are congruent to the hypotenuse and one leg of the another triangle, then the triangles are congruent.</em>

Given ACB and DFE are right triangles.

To prove ΔACB ≅ ΔDFE:

In ΔACB and ΔDFE,

AC ≅ DF (one side)

∠ACB ≅ ∠DFE (right angles)

AB ≅ DE (hypotenuse)

∴ ΔACB ≅ ΔDFE by HL theorem.

6 0
3 years ago
Find the area of a circle with a diameter of 6. Either enter an exact answer in terms of pi or use 3.14 for pi
ankoles [38]
So it gives you the diameter but you need the radius of the circle to find the area so to find the radius you just divide the diameter by two. the formula for the area of a circle is A=pi*r^2 so you just multiply 3.14 by 3 squared so you just put it in the calculator as A=3.14*3^2 and you get 28.26 hope this helped
4 0
2 years ago
1
VashaNatasha [74]

Answer:

B

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 2 and c = - 2 , then

y = - 2x - 2 ← is the equation of the line

To find the x- intercept let y = 0 in the equation and solve for x , that is

- 2x - 2 = 0 ( add 2 to both sides )

- 2x = 2 ( divide both sides by - 2 )

x = - 1

The x- intercept is - 1 → B

5 0
2 years ago
What are the solutions of the system?
siniylev [52]
y=x^2-3x+2 \\y=4x-4

A. (1, 0) and (–6, –28) 

B. (1, 20) and (6, 0) 

C. (1, 0) and (6, 20) 

D. no solution


Correct answer is C.


y=x^2-3x+2 \\y=4x-4\\ \\4x-4=x^2-3x+2 \\x^2-7x+6=0 \\x^2-6x-x+6=0 \\x(x-6)-(x-6)=0 \\(x-6)(x-1)=0 \\x=6\,\text{ or }x=1 \\y=4\times 6-4=20 \,\text{ or }y=4\times 1-4=0 \\ \\(6,20)\,\text{ and }(1,0)

8 0
3 years ago
Read 2 more answers
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