To add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈ end {array} gives <u>A) 399</u>.
<h3>What is an array?</h3>
An array is a data structure made up of some elements.
The sum of all elements in an array is found by adding up the elements in the array.
<h3>Data and Calculations:</h3>
Elements of the array = 37, 202, and 160
The sum of the array, 37 + 202 + 160 = 399
Thus, to add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈ end {array} gives <u>A) 399</u>.
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<h3>Question:</h3>
Add beg ∈ {array} {r} 37 \202\ + 160/ ∈ end {array}
<h3>Answer Options:</h3>
A) 399
B) 389
C) 400
D) 409
Answer:
4.4444
Step-by-step explanation:

For angle B, the opposite leg is 40, and the adjacent leg is 9.


x is less than or equal to -2.
x is greater than -5.
When x is less than something, the arrow must go left. <———
When x is equal to a number, the dot must be filled in. •
When x is greater than a number, the arrow should go right, toward the greater values. ——>
When x isn’t equal to the number, the circle is not colored in. ⭕️
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The height of the flag pole which is described as in the task content is; 8.2m.
<h3>What is the height of the flagpole as described from the top of the 6m house?</h3>
The horizontal distance between the 6m house and the flagpole in discuss can be evaluated by means of the angle of depression and trigonometric identity, tan as follows;
tan 22° = 6/x
x = 6/tan 22 = 14.9m.
Consequently, the horizontal distance from the top of the house to the top of the flagpole is therefore;
tan 9° = y/14.9
y = 14.9 tan 9° = 2.2m
Ultimately, the height of the flagpole is; 6+2.2 = 8.2m.
Read more on trigonometric identities;
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Answer:
x=65
Angle 1=65
Angle 2=115
Step-by-step explanation:
We know that angle 1 + angle 2 = 180. Writing it in terms of x, we get x + (x + 50)= 180. Then you have 2x+50=180. Subtracting 50 from both sides gives you 2x=130. Dividing both sides by 2, you get x=65. Angle 1 is 65 degrees. 180-65=115.